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Nimfa-mama [501]
3 years ago
12

Simplify. x-2/(x^2+4x-12)

Mathematics
1 answer:
Serhud [2]3 years ago
6 0
In order to solve this you need to factor the denominator. 
x^2 +4x - 12
I see that 12 is a product of 6 and 2 and 4 and 3 and 1 and 12.
I pick the two products that, when added together, give me the 4x term.
Here it's 6 and two I just need to make one of them a negative.
now put them in this form:
(x + 6)(x-2) 
In the fraction I see that there is an x-2 in the numerator. This can cancel out with the x-2 in the denominator. Now you have 1/x-6 but remember you can never have a zero in the denominator so x can't equal -6. 
And you're done!

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(3,-25)

Step-by-step explanation:

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The factored form would be (8g + 7h)(2g - 5h)

Step-by-step explanation:

In order to find this, we need to use factors of 16g^2 in the front of the parenthesis. We also need to use factors of -35h^2 in the second side. Now we try these in the parenthesis and FOIL until we get an appropriate middle term.

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What are the coordinates of the inflection point on the graph of y=(x+1)arctanx
Dennis_Churaev [7]

Inflection point is the point where the second derivative of a graph is zero.

y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2

Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2

Therefore, E(1, pi/2).


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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Answer:

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Step-by-step explanation:

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3 0
3 years ago
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