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Katena32 [7]
4 years ago
9

Study the equation. x² + 6x = - 4

Mathematics
1 answer:
Zinaida [17]4 years ago
5 0

Answer:

x = -3+√5,  -3-√5 (exact roots)

or  x = -0.76, -5.24   to the nearest hundredth.

Step-by-step explanation:

x² + 6x = - 4

Completing the square:

(x + 3)^2 - 9 = -4

(x + 3)^2 = 5

x + 3 = +/-√5

x = - 3 + √5, - 3 - √5

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What is the surface area of this rectangular prism?
Sloan [31]
Hello!

First of all, let's find the area of the bases. We can see that the base is 8 by 6, or 48. We have this onto the top as well. This gives us 96. We can multiply The area of each side (base,front, side) by two to get the other side. Then we will add.

48(2)=96 (Base)
42(2)=84 (Side)
56(2)=112 (Front)

Now we add all of our numbers up.

96+84+112=292

Therefore, our answer is B) 292 in²

I hope this helps!

6 0
3 years ago
The ground floor of a building is 18 feet in height and each floor above it is 12 feet in height.
nadezda [96]
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5 0
3 years ago
What’s the slope of -2x+8
77julia77 [94]

Answer:

<h2>The slope m = -2</h2>

Step-by-step explanation:

The slope-intercept form of the equation of line:

y=mx+b

We have

y=-2x+8

Therefore we have the slope = -2.

6 0
4 years ago
50 students went to Verona. 23 were boys. What percentage were giris?
FrozenT [24]

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54 percent

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5 0
3 years ago
Read 2 more answers
Determine the number of real solutions each quadratic equation has. y = 12x2 - 9x 4 real solution(s) 10x y = -x2 2 real solution
nordsb [41]

All the given equations have 2 real solutions except for equation 4 which has only one real root.

<h3>What is a quadratic equation?</h3>

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

The given quadratic equation

y = 12x^2 - 9x+ 4

where, a = 12, b = -9 and c = 4

x = -b + \sqrt{b^2 - 4ac} /2a

x = -(-9)+ \sqrt{(-9)^2 - 4(12)(4)} /2(12)

x = 1.063 or -0.313

Second Equation

10x +y = -x^2 +2 \\y = x^{2} +10x - 2

where, a = 1, b = 10, c = -2

substitute the values into the equation

x = -b + \sqrt{b^2 - 4ac} /2a

-10 + \sqrt{10^2 - 4(1)(-2)} /2(1)

x = 0.195 or -10.195

Third Equation

4y - 7 = 5x^2 - x +2 +3y

y = 5x^{2} -x -5

where, a = 5, b = -1, c = - 5

x = -b + \sqrt{b^2 - 4ac} /2a

-(-1) + \sqrt{(-1)^2 - 4(5)(-5)} /2(5)

x = 0.905 or -0.55

Fourth Equation

y = (-x +4)^2 \\y = x^{2} -8x +16

where, a = 1, b = -8, c = 16

x = -b + \sqrt{b^2 - 4ac} /2a

x = -(-8) + \sqrt{(-8)^2 - 4(1)(16)} /2(1)

x = 4

Learn more about quadratic equations;

brainly.com/question/13197897

6 0
2 years ago
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