Answer:
1/5, 1/6, 1/7, 1/8
Step-by-step explanation:
The formula for the sequence is (n+3)!/ (n+4)!
The first terms uses n=1
a1 = (1+3)!/ (1+4)! = 4!/5! = (4*3*2*1)/(5*4*3*2*1) = 1/5
The first terms uses n=2
a2 = (2+3)!/ (2+4)! = 5!/6! = (5*4*3*2*1)/(6*5*4*3*2*1) = 1/6
The first terms uses n=3
a3 = (3+3)!/ (3+4)! = 6!/7! = (6*5*4*3*2*1)/(7*6*5*4*3*2*1) = 1/7
The first terms uses n=4
a4 = (4+3)!/ (4+4)! = 7!/8! = (7*6*5*4*3*2*1)/(8*7*6*5*4*3*2*1) = 1/8
Functions and equations
We have that:
Let's name each side of it with f(x) and g(x):
Then, we have that:
Then, the answer is C
<h2>
Answer: C</h2>
Answer:
OD Divide both sides of the equation by 2.
Step-by-step explanation:
49/9=m/n this is because you multiply by the reciprocal of 3/7
