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yuradex [85]
3 years ago
11

How has the used of computers and advances in technology changed the healthcare industry

Computers and Technology
1 answer:
mestny [16]3 years ago
4 0
In many, many ways. Here's some things you can talk about:

•Previously we stored patient data by hand on paper. Now we use computers to store it. This is better because what if we accidentally lost/destroyed the papers or it burned down? With computers this risk is minimised.

•We can now diagnose patients with problems with much more precision thanks to advances like MRI scanning, CT scans, and X-rays. This means we can pinpoint problems rather than guess what’s wrong.

•Prescriptions for medicine can now be arranged online and delivered to your door in some areas, whereas previously you would have to walk in and get the medicine which could be time consuming.

•We now have phones to dial 911 for emergency ambulance services. This has revolutionised how quickly responders can respond to life threatening events.

There’s much more to talk about, but all of the points above are a sold start.
You might be interested in
After your yearly checkup, the doctor has bad news and good news. The bad news is that you tested positive for a serious disease
umka2103 [35]

Answer:

The probability that you have the disease, given that your test is positive is ≈ 0.0098

Explanation:

This is a conditional probability problem.

Let P(A|B) denote the conditional probability of A given B and it satisfies the equation

  • (1) P(A|B) = P(A) × P(B|A) / P(B)

We have the the probabilities:

  • P(Testing Positive | Having Disease) =0.99
  • P(Testing Negative | Not Having Disease) =0.99
  • P(Testing Positive | Not Having Disease) = 1-0.99=0.01
  • P(Having Disease) = 0.0001 (striking only one in 10,000 people)
  • P(Not Having Disease)= 1 - 0.0001 = 0.9999

<u>We can calculate</u>:

P(Testing Positive) =

P(Having Disease) × P(Testing Positive | Having Disease) + P(Not Having Disease) × P(Testing positive | Not Having Disease )  = 0.0001×0.99 + 0.9999×0.01 =0.010098

<u>from </u><u>(1) </u><u>we have the equation</u>:

P(Having Disease|Testing Positive)=P(Having Disease) × P(Testing Positive | Having Disease)/ P(Testing Positive) = 0.0001×0.99/0.010098≈0.0098

Thus, the probability that you have the disease, given that your test is positive is ≈ 0.0098

3 0
4 years ago
Is data mining a simple transformation or application of technology developed from databases, statistics, machine learning, and
frozen [14]

Answer:

No.

Explanation:

Data mining is a process that involves extracting large data from a database to be used in data analytics. It is a tool in analytics for provision of wanted data.

It uses databases, statistics, machine learning and pattern recognition to extract, clean and cluster data based on data types classification. It involves integration of data rather than just a simple transformation.

7 0
3 years ago
Read 2 more answers
Write a Twitter class that sets the Twitter user first (who is to be followed) and lets the client add up to 5 followers, which
SSSSS [86.1K]

Answer:

C++ code explained below with its sample outputs

Explanation:

Twitter.h

========

#ifndef Twitter_h

#define Twitter_h

#include <iostream>

using std::string;

using std::cout;

using std::endl;

template <typename T>

class Twitter

{

private:

string name;

T followers[5];

int numFollowers;

public:

Twitter(string n);

bool AddFollower(T follower);

bool RemoveFollower(T follower);

void PrintFollowers();

};

template <typename T>

Twitter<T>::Twitter(string n)

{

name = n;

numFollowers = 0;

}

template <typename T>

bool Twitter<T>::AddFollower(T follower)

{

if(numFollowers < 5)

{

followers[numFollowers] = follower;

numFollowers++;

return true;

}

else

return false;

}

template <typename T>

bool Twitter<T>::RemoveFollower(T follower)

{

int index;

bool found = false;

for(index = 0; index < numFollowers; index++)

{

if(followers[index] == follower)

{

found = true;

break;

}

}

if(found)

{

//shift all other followers after the one to be removed to one position left

for(++index; index < numFollowers; ++index)

{

followers[index-1] = followers[index];

}

numFollowers--;

return true;

}

else

return false;

}

template <typename T>

void Twitter<T>::PrintFollowers()

{

cout << "Followers for " << name << endl;

for(int i = 0; i < numFollowers; i++)

cout << followers[i] << endl;

 

cout << "------" << endl << endl;

}

#endif /* Twitter_h */

main.cpp

=========

#include "Twitter.h"

#include <iostream>

using namespace std;

struct Profile {

string userName;

int age;

string state;

};

 

ostream& operator << (ostream & output, Profile p) {

output << p.userName;

return output;

}

bool operator == (const Profile &p1, const Profile p2)

{

return p1.userName == p2.userName;

}

int main()

{

Twitter<string> t1("John");

Twitter<Profile> t2("Bob");

 

cout << "Adding followers to John" << endl;

t1.AddFollower("Bill");

t1.AddFollower("Jack");

t1.PrintFollowers();

 

Profile p1 = {"Alice", 20, "Alaska"};

Profile p2 = {"Janet", 22, "California"};

Profile p3 = {"Jim", 20, "Texas"};

 

cout << "Adding follower profiles to Bob" << endl;

t2.AddFollower(p1);

t2.AddFollower(p2);

t2.AddFollower(p3);

t2.PrintFollowers();

 

cout << "Removing Bill from John" << endl;

t1.RemoveFollower("Bill");

 

cout << "Removing Janet's profile from Bob" << endl << endl;

t2.RemoveFollower(p2);

 

t1.PrintFollowers();

t2.PrintFollowers();

 

 

 

}

output

-======

Adding followers to John

Followers for John

Bill

Jack

------

Adding follower profiles to Bob

Followers for Bob

Alice

Janet

Jim

------

Removing Bill from John

Removing Janet's profile from Bob

Followers for John

Jack

------

Followers for Bob

Alice

Jim

------

6 0
3 years ago
For angular how can we set up th edatabse.
lesya [120]
You can not communicate directly between Angular and MySQL. You'll need to build a back-end Web service that calls MySql using php or node. Angular can communicate with this back-end Web service via http.
8 0
3 years ago
Using the physical mail analogy, what part of an address on an envelope is most like the ip address?
Slav-nsk [51]
The recipient IP address would would be the recipient home address. 
8 0
3 years ago
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