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Elanso [62]
3 years ago
7

You’ve been stuck in bumper-to-bumper traffic for nearly an hour on a hot summer day. The temperature warning light has just com

e on. How will you handle this situation? What safety precautions will you take?
Computers and Technology
1 answer:
nekit [7.7K]3 years ago
6 0

Answer:

In a bumper-to-bumper traffic, when the engine starts overheating the situation can be handled by tapping the accelator which will revive the engine.

Explanation:

Overheating of engine can be due to many reasons. But one should know what to do when an engine overheats in a traffic. Bumper-to-bumper traffic is when the cars are so close in traffic that they touch each other. This usually happens when there's a traffic for a long time or on very busy lane. During summer times, it is important to keep checking the engine temperature to avoid any problem.

When one is stuck in bumper-to-bumper traffic with overheating engine, then there are some meausres that one can take. They are:

  • To put the car on park or neutral mode of driving and tap the accelator which will revive the engine.
  • The heat can be disperse by rolling down the window and turn the heater up. It will disperse the heat.

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Hydraulic pressure is the same throughout the inside of a set of brake lines. What determines the amount of resulting mechanical
cestrela7 [59]

Answer: 1000 square ponds of force hope you know the answer

Explanation: i guessed

7 0
2 years ago
A Web site that allows users to enter text, such as a comment or a name, and then stores it and later display it to other users,
balandron [24]

Answer:

Option(c) is the correct answer.

Explanation:

Cross-site scripting is the type of security breach that are usually found in the  software applications.The main objective of cross site scripting it is used by the hackers to exploit the data security.

  • The cross site scripting is the collection of web pages  that enables people to insert the text like comment,  name stores it afterwards it save the data and then  it appears to the other users.
  • Others options are incorrect because they are not related to given scenario.
5 0
3 years ago
Read 2 more answers
When a table is displayed in datasheet view, each column represents a select one:
Ksivusya [100]
The answer a. record in the table.
5 0
3 years ago
Write a function with two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The func
Allisa [31]

Answer:

Here is the program:

#include <iostream>  //to use input output functions

#include <string>  // to use functions to manipulate strings

using namespace std;  //to identify objects cin cout

void function(string prefix, unsigned int levels){  // function that takes two parameters, a string, using the string class and levels an unsigned integer

   if (levels == 0) {  //if number of levels is equal to 0

       cout << prefix << endl;  //displays the value of prefix

       return;    }  

  for (int i = 1; i <=9 ; i++){  //iterates 1 through 9 times

       string sections = (levels == 1 ? "" : ".");  //if the number of levels is equal to 1 then empty space in sections variable otherwise stores a dot

       string output = prefix +  std::to_string(i) + sections;   // displays the string prefix followed by the section numbers. Here to_string is used to convert integer to string

       function(output, levels - 1);   } }   //calls function by passing the resultant string and levels-1  recursively to print the string prefix followed by section numbers

int main() {  // start of main function

   int level = 2;  //determines the number of levels

   function("BOX", level);  } //calls function by passing the string prefix and level value

Explanation:

The program has a function named function() that takes two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The function prints the string prefix followed by "section numbers" of the form 1.1., 1.2., 1.3., and so on. The levels argument determines how many levels the section numbers have. If the value of levels is 0 means there is 0 level then the value of prefix is printed. The for loop iterates '1' through '9' times for number of digits in each level. If the number of levels is 1 then space is printed otherwise a dot is printed. The function() calls itself recursively to print the prefix string followed by section numbers.

Let us suppose that prefix = "BOX" and level = 1

If level = 1 then the loop for (int i = 1; i <=9 ; i++) works as follows:

At first iteration:

i = 1

i <=9 is true because value of i is 1

string sections = (levels == 1 ? "" : "."); this statement checks if the levels is equal to 1. It is true so empty space is stored in sections variable so,

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement has prefix i.e BOX plus value of i which is 1 and this int value is converted to string by to_string() method plus sections has an empty space. So this statement becomes

string output = BOX + 1  

So this concatenates BOX with 1 hence output becomes:

output = BOX1

At second iteration:

i = 2

i <=9 is true because value of i is 2

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 2  

So this concatenates BOX with 1 hence output becomes:

output = BOX2

At third iteration:

i = 3

i <=9 is true because value of i is 3

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 3  

So this concatenates BOX with 1 hence output becomes:

output = BOX3

Now at each iteration the prefix string BOX is concatenated and printed along with the value of i. So at last iteration:

At last iteration:

i = 9

i ==9 is true because value of i is 9

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 9  

So this concatenates BOX with 1 hence output becomes:

output = BOX9

After this the loop breaks at i = 10 because the condition i<=9 becomes false. So the output of the entire program is:

BOX1                                                                                                                                          BOX2                                                                                                                                          BOX3                                                                                                                                          BOX4                                                                                                                                          BOX5                                                                                                                                          BOX6                                                                                                                                          BOX7                                                                                                                                          BOX8                                                                                                                                          BOX9  

The program along with the output is attached.

4 0
3 years ago
What is the answer to 7.4.4: Length of User's Name codehs
Alik [6]

The program that ask the user to type there first name and then print out how many letters that is in there name is as follows:

x = input("what is your first name: ")

y = len(x)

print(f"There are {y} letters in your name")

<h3>Code explanation;</h3>

The code is written in python.

  • Firstly, we store the users name in the variable x.
  • Then, we find the length of the users inputted name and store it in a variable y.
  • Finally, we print the length of the users name using the print function.

learn more on python here: brainly.com/question/26738945

4 0
2 years ago
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