Answer:
(A) There should have been 5 outcomes of HT
(B) The experimental probability is greater than the theoretical probability of HT.
Step-by-step explanation:
Given
-- Sample Space
--- Sample Size
Solving (a); theoretical outcome of HT in 20 tosses
First, calculate the theoretical probability of HT
Multiply this by the number of tosses
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Solving (b); experimental probability of HT
Here, we make use of the table
---- Experimental Probability
In (a), the theoretical probability is:
---- Experimental Probability
By comparison;
Amplitude:4
Equation of Midline: 2
Period of function:3
Function shifted left:0.5
Function shifted up: 2
9514 1404 393
Answer:
2
Step-by-step explanation:
The second step of the solution shows division by 2 on the left. Consequently, it must also show division by 2 on the right.
2 goes in the green box
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Well, first of all, the first statement (ABC = ADC) looks like it just says
that the two halves of the little square ... each side of the diagonal ...
are congruent. That's no big deal, and it's no help in answering the
question.
The effect of the dilation is that all the DIMENSIONS of the square
are doubled ... each side of the square becomes twice as long.
Then, when you multiply (length x width) to get the area, you'd have
Area = (2 x original length) x (2 x original width)
and that's
the same as (2 x 2) x (original length x original width)
= (4) x (original area) .
Here's an easy, useful factoid to memorize:
-- Dilate a line (1 dimension) by 'x' times . . . multiply the length by x¹
-- Dilate a shape (2 dimensions) by 'x' . . . multiply area by x²
-- Dilate a solid (3 dimensions) by 'x' . . . multiply volume by x³
And that's all the dimensions we have in our world.
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Oh, BTW . . .
-- Dilate a point (0 dimensions) by 'x' . . . multiply it by x⁰ (1)
Answer:
To solve this problem, you would create two ratios and make them equal to each other, both representing laps:minute or laps/minute! With that being said, laps will be in the numerator, or on top, and minutes will be in the denominator, or the bottom! The first ratio, which we know from the problem, will be 5/8. In order to write the second ratio, we need to come up with something to put in place for what we're solving for. I like to use x. So, we need to find how many laps (x) are run in 1 minute. Remember, laps are on top and minutes are on the bottom. The second ratio would look like x/1. Then we make them equal to each other -> 5/8=x/1. You would then solve this equation by multiplying the right side of the equation by the reciprocal of the denominator! So, it would be 1/1(5/8)=x. Because then multiple the numerators and the denominators -> 1(5)=5 and 1(8)=8! This makes the equation turn into x=5/8! Because x equals the number of laps run in one minute, we can say that Ricky ran 5/8 of a lap in one minute or 0.625 laps in one minute!
Step-by-step explanation:
