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3 years ago

Calcule (1/2)-² POR FAVOR RESPONDEM

Mathematics

1 answer:

dolphi86 [110]3 years ago

4 0

Answer:

I think it's 1/4 or .25

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19.5+24+7.5 = 19.5+__+24 = ___+24+___=

krek1111 [17]

See attached photo for solution

please give a thanks or brainliest if you found my answer helpful :)

8 0

3 years ago

(2x + 5x - 3) + (x + 3)

IrinaK [193]

Answer:

Step-by-step explanation:

Because you are adding the (x+3) there you can immediately you the association property to simplify

(2x + 5x + x) + (3 - 3)

8x + 0 =

5 0

3 years ago

Please!!! Help!!! Brainliest of Right! it goes as 50 point in the end but i used 100 point if you help me i will help you!!

vekshin1

Answer:

2. 3.913 kg (3 dp)

3. light cream

4. 240 CoffeeStops

5. 7 CoffeeStops per square mile

6. 2,861 cups of coffee each day

Step-by-step explanation:

Given:

Skim milk density at 20 °C = 1.033 kg/l
Light cream density at 20 °C = 1.012 kg/l
1 liter = 0.264 gallons

Question 2

$\begin{aligned}\textsf{1 gallon} & = \sf \dfrac{1}{0.264}\:liters\\\\\implies \textsf{Mass (1 gallon of skim milk)} & = \sf Density \times Volume\\& = \sf 1.033\:kg/l \times \dfrac{1}{0.264}\:l\\& = \sf 3.913\:kg\:(3\:dp)\end{aligned}$

Therefore, the mass of 1 gallon of skim milk is 3.913 kg (3 dp)

---------------------------------------------------------------------------------------------

Question 3

Given:

Volume of liquid = 9 liters
Mass of liquid = 9.108 kg

$\begin{aligned}\implies \sf Density & = \sf \dfrac{Mass}{Volume}\\\\& = \sf \dfrac{9.108\:kg}{9\:l}\\\\& = \sf 1.012\:kg/l \end{alilgned}$

Therefore, the container holds light cream.

---------------------------------------------------------------------------------------------

Question 4

Given:

15 CoffeeStops per 100,000 people
Population of Manhattan ≈ 1,602,000 people

$\begin{aligned}\implies \textsf{Number of Coffeestops} & = \sf \dfrac{population}{density}\\\\& = \sf \dfrac{1,602,000}{100,000/15}\\\\& = \sf \dfrac{1,602,000}{100,000} \times 15\\\\& = \sf 240.3\end{aligned}$

Therefore, there are 240 CoffeeStops.

---------------------------------------------------------------------------------------------

Question 5

Given

Manhattan ≈ 34 square miles

$\begin{aligned}\implies \textsf{CoffeeStops density} & = \sf \dfrac{number\:of\:stores}{land\:area}\\\\& = \sf \dfrac{240}{34}\\\\& \approx \sf 7 \: \textsf{CoffeeStops per square mile}\end{aligned}$

Therefore, the density of CoffeeStops is 7 per square mile.

---------------------------------------------------------------------------------------------

Question 6

Given:

Each person buys 3 cups of coffee per week

$\begin{aligned}\implies \textsf{Cups served each week} & = \textsf{number of people} \times \textsf{number of cups per week}\\& = \sf 1,602,000 \times 3\\& = \sf 4,806,000\: \textsf{cups per week}\\\\\implies \textsf{Cups per day} & = \sf \dfrac{\textsf{cups per week}}{\textsf{days in a week}}\\\\& = \sf \dfrac{4,806,000}{7}\\\\& = \sf 686,571\:\textsf{(nearest whole number)}\end{aligned}$

$\begin{aligned}\implies \textsf{Cups served per day per shop} & = \dfrac{\textsf{cups per day}}{\textsf{number of shops}}\\\\& = \sf \dfrac{686,571}{240}\\\\& = \sf 2,861\: \textsf{(nearest whole number)} \end{aligned}$

Therefore, each Manhattan CoffeeStop serves approximately 2,861 cups of coffee each day.

7 0

2 years ago

Kayla and Camille, both teachers, are adding books to their class libraries. Kayla’s classroom started out with a collection of

Airida [17]

34
because, 34 = 14 + (10 x 2)
and 34 = 24 + (10 x 1)

4 0

4 years ago

math problem Just before a referendum on a school budget, a local newspaper polls 400 voters in an attempt to predict whether th

Readme [11.4K]

Answer:

The conditions necessary for the analysis are met.

The probability the newspaper’s sample will lead them to predict defeat is 0.7881

Step-by-step explanation:

We are given;

population proportion; μ = 52% = 0.52

Sample size;n = 400

The conditions are;

10% conditon: sample size is less than 10% of the population size

Success or failure condition; np = 400 x 0.52 = 208 and n(1 - p) = 400(1 - 0.52) = 192.

Both values are greater than 10

Randomization condition; we assume that the voters were randomly selected.

So the conditions are met.

Now, the standard deviation is gotten from;

σ = √((p(1 - p)/n)

where;

p is the population proportion

n is the sample size

σ is standard deviation

Thus;

σ = √((0.52(1 - 0.52)/400)

σ = √((0.52(0.48)/400)

σ = 0.025

Now to find the z-value, we'll use;

P(p^ > 0.5) = P(z > (x - μ)/σ)

Thus;

P(p^ > 0.5) = P(z > (0.5 - 0.52)/0.025)

This gives;

P(p^ > 0.5) = P(z > - 0.8)

This gives;

P(p^ > 0.5) = 1 - P(z < -0.8)

From the table attached we have a z value of 0.21186

Thus;

P(p^ > 0.5) = 1 - 0.21186 = 0.7881

Thus, the probability the newspaper’s sample will lead them to predict defeat is 0.7871

8 0

3 years ago

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Calcule (1/2)-² POR FAVOR RESPONDEM​

Calcule (1/2)-² POR FAVOR RESPONDEM