The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
It’s not 100 points it’s only five points
8x + 3× + 9x = 180
20x = 180
x = 180/20
x = 9
The smallest angle is: 3×9 = 27 degrees
Note: 180 degrees is the sum of angles in a triangle
Hello there!
The statement that would NOT be true would be option A. All isosceles triangles are also equilateral triangles. The rest of the statements would be TRUE.
Hope this helps and have a great day! :)
Answer:
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Step-by-step explanation:
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