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mestny [16]
3 years ago
12

Can you explain how to solve this?

Mathematics
2 answers:
marin [14]3 years ago
5 0
Squaring both sides:
5x - 2 =  4(2x - 5)
5x - 2 = 8x - 20
3x = 18 
x = 6 Answer

seraphim [82]3 years ago
3 0
You can get on math papa it’s totally free and it shows you how to solve it and it shows you the steps and the answers
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60 marks out of 75 full marks<br>express in percent<br><br>​
DochEvi [55]
80 percent

Explanation:
Divide 60 by 75 and get the outcome of .80
3 0
3 years ago
Read 2 more answers
Solve for X......:) &lt;3
Vedmedyk [2.9K]

Answer:

x = 88

Step-by-step explanation:

All angles in a triangle equal 180 degrees. So our equation will be:

x + 48 + (x - 44) = 180

x + 48 + x - 44 = 180

2x + 48 - 44 = 180

2x + 4 = 180

2x = 176

x = 88

Hope this helps!

8 0
3 years ago
$5000 at a 5% interest for 3 1/2 years
larisa [96]
5,875 is the answer
4 0
4 years ago
Juan runs a total of 11,775 feet around a circular track, burning 12 calories each lap. The track’s diameter is 150 feet. How ma
kozerog [31]

Answer:

300 calories

Step-by-step explanation:

he burns 12 calories each lap so you need to know how many laps he ran

which means you need to find the circumference of the track, whose formula is 2πr; remember, radius is half the diameter.

C = 2π75

C = 150π

C ≈ 471

Now divide the total number of feet he ran (11,775) by the circumference to arrive at the number of laps.

11775 ÷ 471 = 25 laps

25 x 12 = 300 calories burned in total

4 0
3 years ago
Hannah has information about an object in circular orbit around Earth. MEarth = 6. 0 × 1024 kg G = 6. 67 × 10–11 StartFraction m
castortr0y [4]

In order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

<h3>What is the tangential speed of the object?</h3>

The tangential speed of an object is the linear component of the speed, which is moving in a circular path.

In terms of  the gravitation constant, the tangential speed can be given as,

v=\sqrt{\dfrac{Gm}{r}}

Here, {<em>G</em>} is the gravitation constant, (<em>m</em>) is the mass and (<em>r</em>) is the radius.

Hannah has information about an object in circular orbit around Earth.

The mass of the earth is.

m_E=6. 0 \times10^{24} kg

The value of gravitational constant is,

G=6. 67\times 10{-11}\rm Nm^2/kg^2

The radius of the earth is,

r_E=6. 0 \times 10^6 \rm m

Here, only the distance of the orbiting object to Earth is need to find the tangential speed of the object.

Hence, in order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

Learn more about the tangential speed here;

brainly.com/question/4933588

7 0
3 years ago
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