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3 years ago

PLEASE HELP!!! WILL MARK BRAINLIEST

Mathematics

2 answers:

rewona [7]3 years ago

8 0

Hello!

I believe the most logical answer is B) Prove that two angles and an included side of one triangle are congruent to two angles and an included side of the other triangle

Hope it helps!

ollegr [7]3 years ago

6 0

a is SSS, c is SAS and d is ASA, all good congruent triangle theorems.

b is AAA, good to show similar triangles, not necessarily congruent triangles.

Answer: b

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Evaluate: f(x) = 2x^2 + 6x - 4; f(-5) *

jasenka [17]

$f(x)=2x^2+6x-4\\$

Find f(-5) by substituting x = -5 in the equation.

$f(-5)=2(-5)^2+6(-5)-4\\f(-5)=2(25)-30-4\\f(-5)=50-34\\f(-5)=16$

Therefore, the answer is f(-5) = 16

8 0

2 years ago

Read 2 more answers

Stephanie is comparing web sites for downloading music. One charges a $5 membership fee plus $0.50 per song. Another charges $1.

Mademuasel [1]

Answer:

0.50x+5=Website A

1.00x=Website B.

Step-by-step explanation:

She would need to buy 10 songs to have them equal the same.

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3 years ago

Find the missing lengths of the sides.

Irina18 [472]

Answer:

The choice third ; a=9 , c= 18

Step-by-step explanation:

$\sin(60) = \frac{9 \sqrt{3} }{c} \\ \\ c = 18$

$\tan(30) = \frac{a}{9 \sqrt{3} } \\ \\ a = 9$

3 0

2 years ago

* WILL GIVE BRAINIEST*

k0ka [10]

Answer:

B: 280

Step-by-step explanation:

The regression line predicts that when x equals 5:

$log_{10}(y) = 2.447$

In order to find the value for y, one must simply apply the following logarithmic property:

if : $log_{b}(a) = c$

then: $b^c = a$

Applying it to this particular problem:

$log_{10}(y) = 2.2447\\10^{2.447}= y\\y=280$

Therefore, the regression line predicts y will equal 280 when x equals 5.

3 0

2 years ago

B. The school prom committee sold presale tickets for

Ivan

Answer:

218 students purchased tickets at the dance.

Step-by-step explanation:

Let,

x be the number of presale tickets

y be the number of tickets sold at the dance

According to given statement;

x+y=334 Eqn 1

18x+24y=7320 Eqn 2

Multiplying Eqn 1 by 18

18(x+y=334)

18x+18y=6012 Eqn 3

Subtracting Eqn 3 from Eqn 2

(18x+24y)-(18x+18y)=7320-6012

18x+24y-18x-18y=1308

6y=1308

$\frac{6y}{6}=\frac{1308}{6}\\y=218$

Therefore,

218 students purchased tickets at the dance.

5 0

2 years ago