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3 years ago

In algebra what is -10+3x=8

Mathematics

2 answers:

Aloiza [94]3 years ago

6 0

The answer is x=15, I hope this help

antiseptic1488 [7]3 years ago

3 0

The answers is X = 6.

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What would be the answer of my fractions <br> 9 1/2 + 4 3/5=

Nina [5.8K]

Answer:

14 $\frac{1}{10}$ or $\frac{141}{10}$

Step-by-step explanation:

Turn your fractions into improper and make them have the same denominator

$\frac{95}{10}$ + $\frac{46}{10}$ = $\frac{141}{10}$

Leave it as is or simplify to 14 $\frac{1}{10}$

8 0

3 years ago

Read 2 more answers

Express the confidence interval

marissa [1.9K]

Answer:

$\hat p = \frac{0.244+0.326}{2}=0.285$

$ME = \frac{0.326-0.244}{2}=0.041$

$0.285 \pm 0.041$

Step-by-step explanation:

For this case we have a confidence interval given as a percent:

$24.4\% \leq p \leq 32.6\%$

If we express this in terms of fraction we have this:

$0.244 \leq p \leq 0.326$

We know that the confidence interval for the true proportion is given by:

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And thats equivalent to:

$\hat p \pm ME$

We can estimate the estimated proportion like this:

$\hat p = \frac{0.244+0.326}{2}=0.285$

And the margin of error can be estimaed using the fact that the confidence interval is symmetrical

$ME = \frac{0.326-0.244}{2}=0.041$

And then the confidence interval in the form desired is:

$0.285 \pm 0.041$

7 0

3 years ago

If a=12, b=3, and c=4 <br> D=a/bc<br> D=?

sineoko [7]

D= (12)/(3)(4)
d = 12/12
d = 1

6 0

3 years ago

Read 2 more answers

exis [7]

Answer:

Part 1) The length of the longest side of ∆ABC is 4 units

Part 2) The ratio of the area of ∆ABC to the area of ∆DEF is $\frac{1}{100}$

Step-by-step explanation:

Part 1) Find the length of the longest side of ∆ABC

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

The ratio of its perimeters is equal to the scale factor

Let

z ----> the scale factor

x ----> the length of the longest side of ∆ABC

y ----> the length of the longest side of ∆DEF

$z=\frac{x}{y}$

we have

$z=\frac{1}{10}$

$y=40\ units$

substitute

$\frac{1}{10}=\frac{x}{40}$

solve for x

$x=(40)\frac{1}{10}$

$x=4\ units$

therefore

The length of the longest side of ∆ABC is 4 units

Part 2) Find the ratio of the area of ∆ABC to the area of ∆DEF

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of ∆ABC

y ----> the area of ∆DEF

$z^{2}=\frac{x}{y}$

we have

$z=\frac{1}{10}$

$z^2=(\frac{1}{10})^2$

$z^2=\frac{1}{100}$

therefore

The ratio of the area of ∆ABC to the area of ∆DEF is $\frac{1}{100}$

3 0

3 years ago

Help please I’m struggling

Sedaia [141]

Answer:

Step-by-step explanation:

45-26=19

6 0

3 years ago

Read 2 more answers