Answer:
WW WI WB WR IW II IB IR BW BI BB BR RW RI RB RR
Step-by-step explanation:
Answer:
Option B. 
Step-by-step explanation:
we know that
If a ordered pair lie on the circle. then the ordered pair must satisfy the equation of the circle
step 1
Find the equation of the circle
we know that
The equation of the circle in center radius form is equal to

where
r is the radius of the circle
(h,k) is the center of the circle
substitute the values


step 2
Verify each case
case A) 
substitute the value of
in the equation of the circle and then compare the results

------> is not true
therefore
the ordered pair Q not lie on the circle
case B) 
substitute the value of
in the equation of the circle and then compare the results

------> is true
therefore
the ordered pair R lie on the circle
case C) 
substitute the value of
in the equation of the circle and then compare the results

------> is not true
therefore
the ordered pair S not lie on the circle
case D) 
substitute the value of
in the equation of the circle and then compare the results

------> is not true
therefore
the ordered pair T not lie on the circle
We are given a right triangle that has angles of 45°-45°-90°. This would
indicate that the triangle is an isosceles type. We can use some
trigonemetric functions to solve for the other legs. We do as follows:
sin 45 = p / 10
p = 5√2
cos 45 = q /10
q = 5√2
<span>Hope this answers the question. Have a nice day.</span>
The weight of an object is the product of its mass and the acceleration of gravity.
If g[e] is the acceleration of gravity on earth, and g[M] the same for Mars and g[m] the same for the moon,
then m[M]=m[e]g[M]/g[e] and m[m]=m[e]g[m]/g[e] where m[ ] denotes mass. Note that weight=mg (measured in newtons) while mass is in kilograms.
If g[M]=g[e]/3 and g[m]=g[e]/6 approximately. Then the weight of an object on Mars will be about a third of what it is on earth, while on the moon it would be about a sixth of what it is on earth.
Answer:
it will be c
Step-by-step explanation: