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OlgaM077 [116]
3 years ago
11

Pick One... To solve the system of equations using the (Elimination, Substitution) method, I would (Multiply Equation 1 by -1 an

d add the equations together, Multiply equation 2 by -3 and add the equation together, Replace X in equation 1 with -x+15, Replace Y in equation 1 with -x+15, or Multiply equation 2 by -1 and add the equations together) in order to solve for Y.

Mathematics
1 answer:
inessss [21]3 years ago
8 0
Elimination, Multiply the second equation by -1, then add the equations together.
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Is 0.158 greater than 0.58
Juli2301 [7.4K]
No. 0.158 is less than 0.58
4 0
3 years ago
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What is the product? (-2x-9y^2)(-4x-3)
telo118 [61]

Answer:-8x^2-6x+36xy^2+27y^2

Step-by-step explanation:

using the FOIL method

6 0
4 years ago
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5*9 (sqrt 10)^3= Help please
Nikitich [7]
Use BODMAS or BIDMAS (Brackets, over Indices, Division, Multiplication, Addition, the Subtraction, this tells you which order to do things in)

As you cant do √10 in the brackets you do the indices, so (√10)³
Split this up to make it easier
(√10)³= √10 x √10 x √10 = 10√10

You the multiply this by 9

9 x 10√10 = 90√10

then multiply by 5

5 x 90√10 = 450√10 = 1423.024947 (using calculator)
7 0
3 years ago
What is the factored form of this polynomial?
oksian1 [2.3K]

Answer:

(x - 4)(x + 9)

Answer C is correct.

Step-by-step explanation:

{x}^{2}  + 5x - 36 \\  {x}^{2}   +  9x  - 4x - 36 \\ x(x  + 9)  -  4(x   +  9) \\  = (x  -  4)(x  + 9)

hope this helps

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4 0
3 years ago
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The base of a triangle exceeds the height by 9 centimeters. If the area is 56 square centimeters, find the length of the base an
shepuryov [24]

Answer:

The height of the triangle is 7cm and the base is 16cm

Step-by-step explanation:

First of all we have to know the formula to calculate area of ​​a triangle

a = area = 56

b = base

h = heigth

a = (b * h)/2

we replace the known values and we make 2 equations

56cm² = (b * h)/2

b = h + 9cm

we replace b by (h + 9cm) in the first equation

56cm² = (h + 9cm * h)/2

56cm² * 2 = h² + 9h

0 = h² + 9h - 112cm²

we use bhaskara formula:

(-b (±) √ (b² - 4ac) ) / 2a

we replace with the known values

h = (-9 (±) √ (9² - 4*1*(-112) ) ) / 2*1

h = (-9 (±) √ (81 + 448) ) ) / 2

h = (-9 (±) √529) /2

h = (-9 (±) 23)/2

h1 = (-9 + 23) / 2

h1 = 14 / 2

h1 = 7

h2 = (-9 - 23) / 2

h2 = -32 / 2

h2 = -16

The height of the triangle is 7cm and the base is 16cm

8 0
3 years ago
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