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Butoxors [25]
4 years ago
14

One of the largest flowers the Rafflesia, weighs about 15 lb. How many Rafflesia flowers can be placed in a container than can h

old a maximum of 240 lbs? *
Mathematics
1 answer:
IRINA_888 [86]4 years ago
7 0

Answer:

16 flowers

Step-by-step explanation:

-Given that a flower weighs 15lb , and the container holds a maximum of 240 lb.

#Divide the capacity of the container by the weight of each flower to find the maximum number held:

Flowers=\frac{Container \ Max \ Weight}{Flower's Weight}\\\\\\=\frac{240}{15}\\\\=16

Hence, the container can hold a maximum of 16 flowers

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Find S5 for a geometric series for which a1=81 and r=1/9.
Minchanka [31]

ANSWER

S_5=91\frac{10}{81}




EXPLANATION


The sum of the first n terms of a geometric sequence is given by;


S_n=\frac{a_1(1-r^n)}{1-r} ,-1


Where n, is the number of terms and a_1 is the first term.


When n=5, we have a_1=81, we get;


S_5=\frac{81(1-(\frac{1}{9})^5)}{1-\frac{1}{9}}


S_5=\frac{81(1-\frac{1}{59049})}{1-\frac{1}{9}}


S_5=\frac{81(\frac{59048}{59049})}{\frac{8}{9}}




S_5=\frac{7381}{81}


S_5=91\frac{10}{81}




6 0
3 years ago
6895 round to nearest thousand​
garik1379 [7]

Answer:

7000

Step-by-step explanation:

8 0
3 years ago
This is the last question which is the fifth one if you can PLS HELP
Trava [24]
I think the answer is b
3 0
2 years ago
Read 2 more answers
F(x) = -x² – 10x + 16<br> Find f(-7)
Gala2k [10]

Answer:

-5

Step-by-step explanation:

or, f(x) = -x^2+10x+16

or, f(7) = (-7)^2+10*-7+16 (-7*-7=49)

=49-70+16

=65-70

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5 0
3 years ago
21÷(4+3)-10 = <br><br> Please help me solve ^^
Dafna11 [192]

Answer:

-7

Step-by-step explanation:

21 ÷ (4+3) - 10

=> 21 ÷ (7) - 10

=> 3 - 10

=> -7

5 0
3 years ago
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