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olga nikolaevna [1]

3 years ago

6

Use transitive property to solve this variable

1 answer:

geniusboy [140]3 years ago

7 0

2z+1=4z+2

2z-4z+1=2
2z-4z=1+2
-2z=1
z=-1/2

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Nutka1998 [239]

$\textsf{Hey there!}$

$\mathsf{\dfrac{3}{5}n +15=10+\dfrac{2}{5}n}$

$\mathsf{\bf{SUBTRACT}\ \mathsf{by\ \dfrac{2}{5}n\ from\ both\ of\ your\ sides}}$

$\mathsf{Like: \dfrac{3}{5}n+15-\dfrac{2}{5}n=\dfrac{2}{5}n+10-\dfrac{2}{5}n}$

$\mathsf{\bf{CANCEL: \dfrac{3}{5}+\dfrac{2}{5}}}\textsf{out\ because that gives you\ 1}$

$\textsf{Solve\ the set we have left over}$

$\mathsf{Our\ new\ equation\ becomes: \dfrac{1}{5}n+15=10}$

$\mathsf{\bf{SUBTRACT}}\textsf{ by 15 on both of your sides}$

$\mathsf{\dfrac{1}{5}n+15-15=10-15}$

$\mathsf{Cancel\ out: 15-15\ because\ that\gives\ you\ 0 }$

$\mathsf{Keep: 10-15\ because\ it\ helps\ us\ solve\ for\ your\ n }$

$\mathsf{10-15=-5}$

$\mathsf{New\ equation: \dfrac{1}{5}n=-5}$

$\mathsf{\bf{MULTIPLY}\mathsf{\ both\ sides\ by\ 5}}$

$\mathsf{\dfrac{1}{5}n\times5=5\times-5}$

$\mathsf{Cancel\ out\ \dfrac{1}{5}\times5 \ because \ it \ gives \ us \ 1}$ $\mathsf{Keep: 5\times -5\ because\ it\gives\ us\ the\ value\ of\ your\ n}$

$\mathsf{n =5\times-5}\\\mathsf{5\times-5 = -25}$

$\textsf{Thus, \underline{\bf{n = -25}}}\checkmark$

$\boxed{\boxed{\mathsf{Thus,\ your\ answer\ is: \boxed{\boxed{\bf{n =-25}}}}}}\checkmark$

$\textsf{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

7 0

2 years ago