The probablity that the sample's mean length is greate than 6.3 inches is0.8446.
Given mean of 6.5 inches,standard deviation of 0.5 inches and sample size of 46.
We have to calculate the probability that the sample's mean length is greater than 6.3 inches is 0.8446.
Probability is the likeliness of happening an event. It lies between 0 and 1.
Probability is the number of items divided by the total number of items.
We have to use z statistic in this question because the sample size is greater than 30.
μ=6.5
σ=0.5
n=46
z=X-μ/σ
where μ is mean and
σ is standard deviation.
First we have to find the p value from 6.3 to 6.5 and then we have to add 0.5 to it to find the required probability.
z=6.3-6.5/0.5
=-0.2/0.5
=-0.4
p value from z table is 0.3446
Probability that the mean length is greater than 6.3inches is 0.3446+0.5=0.8446.
Hence the probability that the mean length is greater than 6.3 inches is 0.8446.
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Answer:
Option B - 
Step-by-step explanation:
Given : Expression 
To find : Expand each expression ?
Solution :
Using logarithmic properties,

and 
Here, A=4y^5 and B=x^2



Using logarithmic property, 

Therefore, option B is correct.
The answer for your question is 12/15
Answer:
I got, when calculated, 209 miles. (It may be wrong)
Step-by-step explanation:
First, I calculated how many miles can Sandeep travel with 1L, therefore I divided 76 miles by 8L and got 9.5 miles on 1L.
Then I multiplied 9.2 miles by 22L and got 209 miles.
This may be wrong but if anyone else is able to work it out much appreciated if it's correct.. Your most welcome!
Those are the ones that are in 50s or
50,51,52,53,54,55,56,57,58,59
10 numbers per hundred
150
250
350
450
550
650
750
850
950
9 of the hundreds
10 per each
9 times 10=90
so there are 90 of them