Answer:
D
Step-by-step explanation:
i hope you uderstand stand why it D
Answer:
Maybe C Sorry if am wrong
Answer:
24414 combinations
Step-by-step explanation:
Solution:-
- We have 17 employees that needs to be managed for a project.
- We will choose all of our employees equally likely for 3 projects.
Project 1 = 8 spacings
- So we have 17 available employees to choose from. So we choose (combinations):
Project 1 = 17C8 = 24310 combinations
- We are left with 17 - 8 = 9 employees, for the next project:
Project 2 = 3 spacings
- So out of the available 9 employees project 2 would have:
Project 2 = 9C3 = 84 combinations
- We are left with 9 - 3 = 6 employees, for the next project:
Project 3 = 3 spacings
- So out of the available 6 employees project 3 would have:
Project 3 = 6C3 = 20 combinations
- The total number of combinations fro selecting 17 employees for each project would be:
24310 + 84 + 20 = 24414 combinations
Answer:
a) e probability that a randomly selected baseball has a weight greater than 5.14 ounces
=P(X>5.14) =(b-x)/(b-a) =(5.155-5.14)/(5.155-5.085)=0.2143
b)
probability that a randomly selected baseball has a circumference less than 9.03 inches
=P(X<9.03) =(x-a)/(b-a) =(9.03-9)/(9.1-9)=0.3
c) probability that a randomly selected baseball will have a weight between 5.11 and 5.13 ounces and a circumference between 9.04 and 9.06 inches
=((5.13-5.11)/(5.155-5.085))*((9.06-9.04)/(9.1-9.0))=0.0571
