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Rashid [163]
3 years ago
6

What is the vertex of g(x)=x^2-14x+54 ?

Mathematics
1 answer:
Iteru [2.4K]3 years ago
4 0
Use the vertex formula x=-b/(2a) Once you find the x, plug it back in to find the y

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Use elimination method to solve the system of equations -x+y=7 and x+y=1
Sauron [17]

Answer:

(x, y)= (-3, 4)

Step-by-step explanation:

eliminate the variable by adding the equations

8 0
3 years ago
A function is created to represent the amount of texts sent each month. What restrictions would be made to the range?. The range
forsale [732]
A range is the amount of time from a start of the action up to the end of the action so in your question where a function is created to present the amount of text sent each month. So the best possible restriction of the range is "The range would only include positive integers"
6 0
4 years ago
Can you please help me.
Tanzania [10]
So basically you would have to divided 300 by 80 to see the other side of the square and that would equal 3.75. But i’m not too sure if would i put us right so double check
8 0
3 years ago
Read 2 more answers
use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r
Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt

If we ask that f has continuous (n+1)th derivative we can apply the mean value theorem for integrals. Then, there exists c between a and x such that

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x

Hence,

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .

Thus,

\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}

and the Taylor theorem with Lagrange remainder is

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}.

Step-by-step explanation:

5 0
3 years ago
Uni made a model of a 1970 Ford Mustang using a scale of .5 inches = 9 in. If the actual car is 15 ft long, how long is the mode
kykrilka [37]

Answer:

The model car is 10 inches long

Step-by-step explanation:

To solve this question, we use conversion of units

Feet to inches.

Each feet has 12 inches.

The car is 15ft long.

So the car has 15*12 = 180 inches.

.5 inches = 9 in.

Rule of three

.5 inches - 9 inches

x inches - 180 inches

9x = 180*0.5

9x = 90

x = \frac{90}{9}

x = 10

The model car is 10 inches long

7 0
3 years ago
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