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Blababa [14]
3 years ago
7

What equation results from completing the squre and then factoring x^2+10=15

Mathematics
1 answer:
nlexa [21]3 years ago
6 0

For this case we must complete squares:

x ^ 2 + 10x = 15

We add the square of half the coefficient of the term "x",

(\frac {b} {2a}) ^ 2 on both sides of the equation:

x^2+10x+(\frac {10} {2 (1)}) ^ 2 = 25 + 15\\x ^ 2 + 10x + 5 ^ 2 = 25 + 15

According to the perfect square trinomial we have:

(a + b) ^ 2 = a ^2 + 2ab + b ^ 2

Rewriting the expression we have:

a = x\\b = 5\\(x + 5) ^ 2 = 25 + 15\\(x + 5) ^ 2 = 40

ANswer:

(x + 5) ^ 2 = 40

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Option 1 <br> y=1/2x - 4 <br> Is this the graph for the equation?
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No, I don't think so.

Step-by-step explanation:

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Suppose 232subjects are treated with a drug that is used to treat pain and 50of them developed nausea. Use a 0.01significance le
Margarita [4]

Answer:

A

   The  correct option is B

B

   t =  0.6093

C

 p-value  =  0.27116

D

The  correct option is  D

Step-by-step explanation:

From the question we are told that

    The  sample size is  n  =  232

    The  number that developed  nausea  is X =  50

    The population proportion is  p  =  0.20  

 

The  null hypothesis is   H_o : p  =  0.20

The  alternative hypothesis is  H_a :  p > 0.20

Generally the sample proportion is mathematically represented as

     \r p  =  \frac{50}{232}

     \r p  =  0.216

Generally the test statistics is mathematically represented as

 =>           t =  \frac{\r p  -  p }{ \sqrt{ \frac{p(1- p )}{n} } }

=>           t =  \frac{ 0.216 - 0.20 }{ \sqrt{ \frac{ 0.20 (1- 0.20 )}{ 232} } }

=>        t =  0.6093

The  p-value obtained from the z-table is

       p-value  =  P(Z >  0.6093) =  0.27116

  Given that the  p-value >  \alpha  then we fail to reject the null hypothesis

5 0
3 years ago
What are the first 6 terms for this arithmetic equation?
Ipatiy [6.2K]

Answer:

3, - 2, - 7, - 12, - 17, - 22

Step-by-step explanation:

To find the first 6 terms substitute n = 1, 2, 3, 4, 5 into the formula, that is

t(1 + 1) = t(1) - 5 ⇒ t(2) = 3 - 5 = - 2

t(2 + 1) = t(2) - 5 ⇒ t(3) = - 2 - 5 = - 7

t(3 + 1) = t(3) - 5 ⇒ t(4)  = - 7 - 5 = - 12

t(4 + 1) = t(4) - 5 ⇒ t(5) = - 12 - 5 = - 17

t(5 + 1) = t(5) - 5 ⇒ t(6) = - 17 - 5 = - 22

3 0
3 years ago
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