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2 years ago

If using SAS to determine if a triangle is unique, you must know:

Mathematics

2 answers:

inessss [21]2 years ago

8 0

Pls picture at least

Sholpan [36]2 years ago

5 0

Answer:

It is important to note that SAS construction will always produce one, unique triangle. It does not matter how much you flip, rotate or move the ...

Step-by-step explanation:

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I asked a question a while ago and nobody has answered it pls help

bogdanovich [222]

Answer:

bet but need barinlyist

Step-by-step explanation:

5 0

3 years ago

Evaluate ab + 3c when a=-6, b=-2, and c=5

ra1l [238]

Do it step by step
ab+3c
(-6)(-2)+3(5)
A negative times a negative is positive. (-)(-)=+
12+3(5)
12+15
=27

8 0

3 years ago

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

2 years ago

How do I solve this problem correctly?

Nat2105 [25]

What is the question for the problem are you trying to figure out area or perhaps perimeter and of what the shaded or non shaded next time include that in your answer.

5 0

3 years ago

What is the slope of the line shown below?

IrinaVladis [17]

Answer:

D. 7/3

Explanation:

Y1 - Y2 / X1 - X2

9 - -5 / 6 - 0

9 + 5 / 6

14 / 6

7/3

3 0

3 years ago