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3 years ago

2,000,000 mg = how many kg?

1 answer:

8 0

$1kg=1,000g\\1g=1,000mg\\\\therefore\\1kg=1,000\times1,000mg=1,000,000mg\to1mg=\frac{1}{1,000,000}kg\\\\2,000,000mg=\frac{2,000,000}{1,000,000}kg=\boxed{2kg}$

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What is the value of 3n if n=2

Harman [31]

Answer:

Step-by-step explanation:

3n=3(n)

ur replcing n with 2

3(2)=3x2

3x2=6

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3 years ago

Read 2 more answers

Is 11/20 greater or less than 1/2

inn [45]

Greater. This is because 1/2 x 10/10 = 10/20. 11>10

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4 years ago

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Determine if the sequence below is arithmetic or geometric and determine the

Sonbull [250]

Answer: Arithmetic and 3

Step-by-step explanation:

12 - 9 = 3 9 - 6 = 3 The common difference is equal and is three and so it is an arithmetic sequence

12/9 = 4/3 9/6 = 3/2 The ratio is not equal so this is not a geometric sequence

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3 years ago

A family has two cars. The first car has a fuel efficiency of 15 miles per gallon of gas and the second has a fuel efficiency of

professor190 [17]

The fuel consumption of each of the cars during the week are as follows;

The first car consumes 20 gallons of fuel.

The second car consumes 30 gallons of fuel.

Reasons:

Fuel efficiency of the first car = 15 miles per gallon

Fuel efficiency of the second car = 35 miles per gallon

Combined distance traveled by the two cars in a week = 1,350 miles

The total gas consumption during the week = 50 gallons

Let x represent the number of gallons consumed by the first car, and let y

represent the number of gallons consumed by the second car, we get the

following system of simultaneous equations;

15·x + 35·y = 1,350...(1)

x + y = 50...(2)

Therefore;

y = 50 - x

Which gives;

15·x + 35 × (50 - x) = 1,350

15·x + 1,750 - 35·x = 1,350

1,750 - 1,350 = 35·x - 15·x = 20·x

400 = 20·x

x = 400 ÷ 20 = 20

The number of gallons consumed by the first car, x = 20 gallons

From equation (2), we have;

x + y = 50

y = 50 - x

Therefore;

y = 50 - 20 = 30

The number of gallons consumed by the second car, y = 30 gallons

Learn more about word problems that lead to simultaneous equations here:

brainly.com/question/1717365

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2 years ago

Elmer has a collection of 300 fossils. Of those, 21% are fossilized snail shells. How many fossilized snail shells does Elmer ha

kakasveta [241]

Use the percent proportion

21 x
—— = ——
100 300

to solve :
21 x 300 = 6300
6300 ÷ 100 = 63

Answer = 63 of Elmer’s shells are fossilized snail shells :)

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3 years ago