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2 years ago

2,000,000 mg = how many kg?

1 answer:

8 0

$1kg=1,000g\\1g=1,000mg\\\\therefore\\1kg=1,000\times1,000mg=1,000,000mg\to1mg=\frac{1}{1,000,000}kg\\\\2,000,000mg=\frac{2,000,000}{1,000,000}kg=\boxed{2kg}$

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Carter has one 20$ bill, one 10$bill, four 5$ bills and two 1$ bill,Aubrey has two 10$bills ,five 5$ bills and seven 1$ bills .w

Luba_88 [7]

Carter- 20+10=30+(5x4)=50+2=$52
Aubrey- 10x2=20+(5x5)=45+7=$52
They both have the same amount of money

8 0

2 years ago

Read 2 more answers

PLS help will give brainliest fill in the blanks only do it if you know its CORRECT

professor190 [17]

Answer:

3 5 = 16

3 = 3 16

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2 years ago

A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th

OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. Calculate the mean

$\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666$

Second step. Calculate the standard deviation

$\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}$

$\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}$

$\sigma=\sqrt{17.815}=4.22$

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

$\bar X \pm t\frac{\sigma}{\sqrt n}$

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

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2 years ago

Write an equation in point slope form of the he that passes through the point (2.1) and has a slope of 2

Wewaii [24]

Answer:

y=2x-3

Step-by-step explanation:

show work

1=(2*2)+b

1=4+b

1-4=-3

-3=b

check work

y=2x-3

y=(2*2)-3

y=4-3

y=1

5 0

2 years ago

Read 2 more answers

The width of a rectangle is 3 less than twice its length. if the area of the rectangle is 193 cm 2 cm2, what is the length of th

sineoko [7]

W=2L-3
W*L=193
replace W with 2L-3: (2L-3)L=193
2L^2-3L-193=0
Cannot factor
are you sure the numbers are correct?
If it cannot be factored, use the quadratic formula to find out L, then you can find out W
use the Pythagorean theorem to find the diagonal. I don't see an easier way.

4 0

3 years ago