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olga_2 [115]
3 years ago
15

The following table shows the​ weights, in hundreds of​ pounds, for six selected cars. Also shown is the corresponding fuel​ eff

iciency, in miles per gallon​ (mpg), for the car in city driving. Use the data provided in the table to complete parts ​a) through​d).
Weight​ (hundreds of​ pounds)

28

33

35

32

30

29

Fuel efficiency​ (mpg)

20

22

19

22

23

21

​a) Determine the correlation coefficient between the weight of a car and the fuel efficiency.

The correlation coefficient between the weight of a car and the fuel efficiency is

r=

​(Type an integer or decimal rounded to three decimal places as​ needed.)
Mathematics
1 answer:
Reika [66]3 years ago
8 0

Answer:

Step-by-step explanation:

Given is a table showing  the​ weights, in hundreds of​ pounds, for six selected cars. Also shown is the corresponding fuel​ efficiency, in miles per gallon​ (mpg), for the car in city driving.

Weight Fuel eff. x^2 xy y^2

X Y    

28 20 784 560 400

3 22 9 66 484

35 19 1225 665 361

32 22 1024 704 484

30 23 900 690 529

29 21 841 609 441

     

Mean 26.16666667 21.16666667 797.1666667 549 449.8333333

     

Variance   112.4722222  1.805555556

Covariance -553.8611111    

     

     

r -0.341120235    

Correlaton coefficient =cov (xy)/S_x S_y

Covariance (x,y) = E(xy)-E(x)E(y)

The correlation coefficient between the weight of a car and the fuel efficiency is -0.341

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Step-by-step explanation:

In the first 168 miles,

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Tcecarenko [31]

Answer:

C. a higher monthly payment.

Step-by-step explanation:

<h3>Answer options:</h3>

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Bob Nale is the owner of Nale's Texaco GasTown. Bob would like to estimate the mean number of litres (L) of gasoline sold to his
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Answer:

a

  The point estimate of the population mean is  \= x  =  56

b

  The 80% confidence level is  50.57 <  \mu  < 61.43

c

  There is  80% confidence that the true population mean lies within the confidence interval.

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  18

   The  standard deviation is  \sigma  =  18 \ L

   The  sample mean is  \= x  =  56

Generally the point estimate of the population mean is equivalent to the sample mean whose value is  \= x  =  56

Given that the confidence interval is 80% then the level of significance is mathematically represented as

      \alpha  =  100 -  80

      \alpha =  20 \%

      \alpha = 0.20

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table

 The  value is   Z_{\frac{ \alpha }{2} } =  1.28

 Generally the margin of error is mathematically evaluated as

          E =  Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }

=>       E =  1.28 * \frac{18 }{\sqrt{18} }

=>       E =  5.43

     Generally the 80% confidence interval is mathematically represented as

    \= x  - E  <  \mu  < \= x  + E

=>    56  - 5.43  <  \mu  < 56  + 5.43

=>   50.57 <  \mu  < 61.43

The  interpretation is that there is  80% confidence that the true population mean lies within the limit

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3 years ago
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