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Leya [2.2K]
3 years ago
9

There is a total of 1,500 people in the town of Markston. Only 55% of them voted during the town's elections this year. How many

people voted? 550 people 675 people 825 people 2,727 people
Mathematics
1 answer:
AfilCa [17]3 years ago
3 0

Answer:

825 people voted in the town of Markston during the elections this year.

Step-by-step explanation:

Hi there!

The total number of people of the town of Markston (1500) is the 100%. Then, the 55% of 1500 can be calculated by multiplying 1500 by 55/100:

55% of 1500 = 1500 · 55/100 = 825

Another way to see this:

If 100% is 1500, then the 55% will be x:

100% -------- 1500

55% ----------- x = 55 · 1500 / 100 = 825

Then, 825 people voted in the town of Markston during the elections this year.

Have a nice day!

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Alison is learning how to walk. 50% of the time that she takes a step she falls down. Her older brother wants to design a simula
MissTica

Answer with explanation:

Alison is learning how to walk.50% of times she takes a step she falls down.

Probability of falling down in next step =\frac{50}{100}=\frac{1}{2}

Probability of not falling down in next step =\frac{50}{100}=\frac{1}{2}

From ,the four option given,we have to find the best simulation which her older brother wants to design a simulation to find the probability that she will fall down 5 out of the next 7 times she tries to take step.

While Simulating the Probability of falling down should be =\frac{5}{7}

And , probability of not falling down1-\frac{5}{7}=\frac{2}{7}

→→⇒F=Falling, NF=Non Falling

A) Roll a die letting 1 represent Alison falling and 2-6 represent Alison not falling. Roll the die five times.

P(F)=\frac{1}{6},P(NF)=\frac{5}{6}

Incorrect option,probabilities of falling and non falling does not match with Actual probability of falling and non falling.  

B) Roll a die letting 1 represent Alison falling and 2-6 represent Alison not falling. Roll the die seven times.

P(F)=\frac{1}{6},P(NF)=\frac{5}{6}

Incorrect option,probabilities of falling and non falling does not match with Actual probability of falling and non falling.

C) Let Heads represent Alison falling down and Tails representing Alison not falling down. Flip the coin five times.

P(F)=\frac{1}{2},P(NF)=\frac{1}{2}

Simulation is done only five times , that is coin has been flipped only five times.it must have been flipped seven times.Incorrect option.  

D) Let Heads represent Alison falling down and Tails representing Alison not falling down. Flip the coin seven times.

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Simulation is done seven times , that is coin has been flipped seven times.So,she should fall 5 times that is head should appear 5 out of seven times, and tail should appear 2 out of seven times.correct option.

Option D

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4 years ago
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