You need to use a ratio of height (H) to shadow length (L) to solve the first problem. It's basically a use of similar triangles, with two perpendicular sides, and with the shadow making the same angle with the vertical.
6 ft = 72 ins, so that rH/L = 72/16 = 9/2 for the player.
So the bleachers are 9/2 x 6 ft = 27 ft.
For the second problem, 9 ft = 108 in, so that the ratio of the actual linear dimensions to the plan's linear dimensions are 9ft/(1/2in) = 2 x 108 = 216.
So the stage will have dimensions 216 times larger than 1.75" by 3".
That would be 31ft 6ins x 54ft.
Live long and prosper.
Answer:
(5,1)
Step-by-step explanation:
if macs house if it’s 1/2 of the distance from Nate house to the park then half the distance of 10,2 is 5,1
Answer:
3
Step-by-step explanation:
10/4 = 2 1/2
2 1/2 + 2/4 = 3
The correct answer is -3 through -6.
Answer:
The equation of the straight line in Slope- intercept form
y = 3 x - 11
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given points are (2,-5) and (8, 13)
The Slope of the line
Equation of the line having slope 'm' and given point
(x₁ , y₁) = ( 2, -5 )
y + 5 = 3x - 6
The equation of the straight line in slope intercept form
y = m x + c
y = 3 x - 6-5
y = 3 x - 11
<u><em>Final answer:</em></u>-
The equation of the straight line in Slope- intercept form
y = 3 x - 11
