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GREYUIT [131]
3 years ago
14

A memory page containing a heavily used variable that was initialized very early and is in constant use is removed, then the pag

e replacement algorithm used is ____________
A. LRU
B. LFU
C. FIFO
D. NONE
Computers and Technology
1 answer:
kompoz [17]3 years ago
7 0

Answer:

C. FIFO

Explanation:

The first-in, first-out (FIFO) page replacement algorithm is a low-overhead algorithm that requires work on the part of the operating system. On a page fault, the frame that has been in memory the longest is replaced.

Using FIFO algorithm implies that

a page which was brought into memory first will be removed first since variable was initialized very early. it is in the set of first in pages that will be removed.

It is the simplest page replacement algorithm. The operating system keeps track of all pages in the memory in a queue, the oldest page is in the front of the queue. When a page needs to be replaced page in the front of the queue is selected for removal that is first in first out.

A memory page containing a heavily used variable that was initialized very early and is in constant use is removed, then the page replacement algorithm used is called First In First Out.

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g Write a function called price_of_rocks. It has no parameters. In a while loop, get a rock type and a weight from the user. Kee
Scilla [17]

Answer:

<u>The pseudocode:</u>

FUNCTION price_of_rocks():

  SET total = 0

  while True:

      INPUT rock_type

      INPUT weight

      if rock_type is "Quartz crystals":

         SET total += weight * 23

      elif rock_type is "Garnets":

         SET total += weight * 160

      elif rock_type is "Meteorite":

         SET total += weight * 15.50

       

       INPUT choice

       if choice is "n":

           break

 

   RETURN total

END FUNCTION

<u>The code:</u>

def price_of_rocks():

   total = 0

   while True:

       rock_type = input("Enter rock type: ")

       weight = float(input("Enter weight: "))

       

       if rock_type == "Quartz crystals":

           total += weight * 23

       elif rock_type == "Garnets":

           total += weight * 160

       elif rock_type == "Meteorite":

           total += weight * 15.50

           

       choice = input("Continue? (y/n) ")

       if choice == "n":

           break

   

   return total

print(price_of_rocks())

Explanation:

Create a function named price_of_rocks that does not take any parameters

Initialize the total as 0

Create an indefinite while loop. Inside the loop:

Ask the user to enter the rock_type and weight

Check the rock_type. If it is "Quartz crystals", multiply weight by 23 and add it to the total (cumulative sum). If it is "Garnets", multiply weight by 160 and add it to the total (cumulative sum). If it is "Meteorite", multiply weight by 15.50 and add it to the total (cumulative sum).

Then, ask the user to continue or not. If s/he enters "n", stop the loop.

At the end of function return the total

In the main, call the price_of_rocks and print

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ZeroIt is a function that takes one argument and returns no value. The argument is a pointer to int. The function stores the val
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Answer:

zeroIt(&x);

Explanation:

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zeroIt(&x);

The zeroIt function is also given below for better understanding.

void zeroIt(int *x) {

   *x = 0;

}

As seen, the function takes an argument with integer variable type, which is a pointer, denoted by the asterisk symbol (*x).

The ampersan sign (&x) is used to access the variable whose value can then be stored.

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