Find the requested information based on the given facts.

This problem uses the teengamb data set in the faraway package. Fit a model with gamble as the response and the other variables

hichkok12 [17]

Answer:

A. 95% confidence interval of gamble amount is (18.78277, 37.70227)

B. The 95% confidence interval of gamble amount is (42.23237, 100.3835)

C. 95% confidence interval of sqrt(gamble) is (3.180676, 4.918371)

D. The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

Step-by-step explanation:

to)

We will see a code with which it can be predicted that an average man with income and verbal score maintains an appropriate 95% CI.

attach (teengamb)

model = lm (bet ~ sex + status + income + verbal)

newdata = data.frame (sex = 0, state = mean (state), income = mean (income), verbal = mean (verbal))

predict (model, new data, interval = "predict")

lwr upr setting

28.24252 -18.51536 75.00039

we can deduce that an average man, with income and verbal score can play 28.24252 times

using the following formula you can obtain the confidence interval for the bet amount of 95%

predict (model, new data, range = "confidence")

lwr upr setting

28.24252 18.78277 37.70227

as a result, the confidence interval of 95% of the bet amount is (18.78277, 37.70227)

b)

Run the following command to predict a man with maximum values for status, income, and verbal score.

newdata1 = data.frame (sex = 0, state = max (state), income = max (income), verbal = max (verbal))

predict (model, new data1, interval = "confidence")

lwr upr setting

71.30794 42.23237 100.3835

we can deduce that a man with the maximum state, income and verbal punctuation is going to bet 71.30794

The 95% confidence interval of the bet amount is (42.23237, 100.3835)

it is observed that the confidence interval is wider for a man in maximum state than for an average man, it is an expected data because the bet value will be higher than the person with maximum state that the average what you carried s that simultaneously The, the standard error and the width of the confidence interval is wider for maximum data values.

(C)

Run the following code for the new model and predict the answer.

model1 = lm (sqrt (bet) ~ sex + status + income + verbal)

we replace:

predict (model1, new data, range = "confidence")

lwr upr setting

4,049523 3,180676 4.918371

The predicted sqrt (bet) is 4.049523. which is equal to the bet amount is 16.39864.

The 95% confidence interval of sqrt (wager) is (3.180676, 4.918371)

(d)

We will see the code to predict women with status = 20, income = 1, verbal = 10.

newdata2 = data.frame (sex = 1, state = 20, income = 1, verbal = 10)

predict (model1, new data2, interval = "confidence")

lwr upr setting

-2.08648 -4.445937 0.272978

The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

4 0

3 years ago

2 Joey runs 4 – miles in of an hour and Chandler runs 2 miles miles in of an hour. Who runs faster

HACTEHA [7]

Answer: Joey is faster

Step-by-step explanation: Because in 1 hour Joey is run 4 mile but in 1 hour Chandler is run 2 mile

6 0

3 years ago

Read 2 more answers

The right triangle shown has angles X, Y, and Z and side lengths a, b, and

laiz [17]

So attached is a picture of the triangle you are talking about and listed under are the choices:

A.) Cos Z=b/c
B.) Sin X=c/b
C.) Tan X=b/a
D.) Tan Z=a/b

The answer would then be B. SinX = c/b.

Just remember SOH CAH TOA:

Sinθ= Opposite Cosθ = Adjacent Tanθ= Opposite
Hypotenuse Hypotenuse Adjacent

Using the triangle in the scenario, you just need to identify which side is which.

Given m∠Z
Adjacent = b
Opposite = a
Hypotenuse = c

SinZ= a CosZ = b TanZ= a
c c b

Given m∠X:

Adjacent = b
Opposite = a
Hypotenuse = c

SinX= b CosX = a TanX= b 
c c a

So the answer is B.

Attached is a picture of how I assigned the sides depending on the angle used.

4 0

3 years ago

Which equation correctly applies the distributive property?

lesantik [10]

Answer: Option 'A' is correct.

Step-by-step explanation:

Since we have given that

Distributive law is defined as

$a\times (b+c+d)=a\times b+a\times c+a\times d$

According to option'A', we get that

a =- 3

b = 6

c = 0.4

d = 0.08

So, it becomes,

$-3\times (6.48)=-3\times 6+(-3)\times 0.4+(-3)\times 0.08$

Hence, option 'A' is correct.

8 0

3 years ago

A password contains six digits, such as 174668. How many different passwords can be formed

STALIN [3.7K]

Answer: The number of different passwords can be formed = 1,000,000

Step-by-step explanation:

In general total digits = 10 [ from 0 to 9]

If a password contains 6 digits, then by fundamental principal of counting, the total number of different passwords = $10\times10 \times10\times10\times10\times10=10^6=1000000$

Hence, the number of different passwords can be formed = 1,000,000

5 0

3 years ago