Find the requested information based on the given facts.

Does a mathematical expression have a solution?

bagirrra123 [75]

It does not contain an equal sign. It cannot be solved for unless the value of the variable is given.

7 0

3 years ago

Please answer

sergeinik [125]

I gotchu! there is no association shown between the two in this sample because the given information only shows the correlation between fur color and environmental and NOT gender.
hope you do amazing have a wonderful night

8 0

3 years ago

Marta is making two different charms for necklace one charm has a 1 cm diameter and a 3.14 centimeter circumference A similar ch

dlinn [17]

Both charms are "similar".

And notice one diameter is 1, the other is 4, the diameters are on a ratio of 1:4 then, and so both figures are on a ratio of 1:4.

so, if another unit, like the circumference is at 3.14 on the small one, then the large one will have a circumference 4 times that much, because the circumferences are also on a 1:4 ratio.

4 0

3 years ago

A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular

Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = $\frac{360}{8}$

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

$sin 22.5=\frac{AC}{OA}$

$=\frac{AC}{x}$

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, $cos 22.5=\frac{OC}{OA}$

$=\frac{OC}{x}$

So, OC = x cos 22.5°.

Area of Δ AOB = $\frac{1}{2}(AB)(OC)$

= $\frac{1}{2}$ × (2x sin 22.5°) × (x cos 22.5°)

= $\frac{1}{2} x^{2}$ (2 sin 22.5° cos 22.5°)

= $\frac{1}{2} x^{2}$ sin 45°

= $x^{2}$ / $2\sqrt{2}$

Area of the octagonal gazebo = 8 × one triangular area

= 8 × ( $x^{2}$ / $2\sqrt{2}$ )

$=2\sqrt{2} x^{2}$

$=2.828x^{2}$

Area required for mulch = circular area - area of the gazebo

$=3.14x^{2} -2.828x^{2}$

$=0.312x^{2}$

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = $0.312x^{2}$ × 1.5

$=0.468x^{2}$

Hence, total cost g(m) = $0.468x^{2}$ .

4 0

3 years ago

Group technology requires that:

kifflom [539]

Answer: e. each component be identified by a coding scheme that specifies size, shape, and the type of processing.

Step-by-step explanation:

Group technology is a technique in manufacturing that involves bringing together parts with similar process of manufacturing or function into the same location so that they can all go through the same process. This follows a general saying that problems with similar groups could possibly be solved using a single or similar solution, which could help save time, resources and efforts.

6 0

3 years ago