It would be the median of the data set
Answer:
Step-by-step explanation:
(x1,y1)and (x2,y2)
This answer would be (-14).
The borders are shown in the picture attached.
As you can see, starting with border 1, we have 6 daises (white squares) surrounded by 10 tulips (colored squares). Through Jerry's expression we expected:
<span>8(b − 1) + 10 =
</span>8(1 − 1) + 10 =
0 + 10 =
10 tulips.
When considering border 2, we expect:
<span>8(b − 1) + 10 =
</span>8(2 − 1) + 10 =
8 + 10 =
<span>18 tulips.
Indeed, we have the 10 tulips from border 1 and 8 additional tulips, for a total of 18 tulips.
Then, consider border 3, we expect:
</span><span>8(b − 1) + 10 =
</span>8(3 − 1) + 10 =
16 + 10 =
26<span> tulips.
Again, this is correct: we have the 10 tulips used in border 1 plus other 16 tulips, for a total of 26.
Therefore, Jerry's expression is
correct.</span>
Answer:
0.1569 = 15.69%
Step-by-step explanation:
If eight calls were placed, and we need to know the probability of exactly two calls were occupied, we need to calculate a combination of 8 choose 2 (all the combinations of 2 occupied calls in the 8 total calls), and multiply by the probability of each case in the 8 calls (2 cases occupied and 6 cases not occupied):
P(8,2) = C(8,2) * p(occupied)^2 * p(not_occupied)^6
P(8,2) = (8*7/2) * (0.45)^2 * (0.55)^6
P(8,2) = 28 * 0.2025 * 0.02768 = 0.1569 = 15.69%