see the attached figure with the letters
1) find m(x) in the interval A,BA (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100
2) find m(x) in the interval B,CB(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20
3)
find n(x) in the interval A,BA (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x
4) find n(x) in the interval B,CB(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30
5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44
6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72
for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72
<span> h'(x) = 1.44 ------------ > not exist</span>
Answer:
3/4 of the same number is 90
Step-by-step explanation:
FIND the unknown number by:
48 ÷ 2/5 = 120
TIP: for finding a fractional part of a number, multiply the fraction by the number. Like:
2/5 of 120 also means 2/5 x 120.
Find 3/4 of 120:
3/4 x 120 = 90
I hope I helped!
-Spacemarsh
Answer:
A = 18 units²
Step-by-step explanation:
The area (A) of a trapezium is calculated as
A =
h ( b₁ + b₂ )
where h is the perpendicular height and b₁, b₂ the parallel bases
By counting squares
h = 3, b₁ = 3, b₂ = 9 , then
A =
× 3 × (3 + 9) = 1.5 × 12 = 18 units²
Answer:
-3
Step-by-step explanation:
(-5) - (-2) = (-3)
hope it helps
The relationship between the sides of the polygon and the triangle follows an arithmetic sequence
The expression that represents the number of triangles is (c) n - 2
From the diagrams, we have:
Sides Triangles
5 3
6 4
8 6
The above can be represented as functions as follows:
![f(5) = 3](https://tex.z-dn.net/?f=f%285%29%20%3D%203)
![f(6) = 4](https://tex.z-dn.net/?f=f%286%29%20%3D%204)
![f(8) = 6](https://tex.z-dn.net/?f=f%288%29%20%3D%206)
Express 6 as 8 - 2
![f(8) = 8 - 2](https://tex.z-dn.net/?f=f%288%29%20%3D%208%20-%202)
Express 8 as n
![f(n) = n - 2](https://tex.z-dn.net/?f=f%28n%29%20%3D%20n%20-%202)
So, the expression that represents the number of triangles is (c) n - 2
Read more about sequence and patterns at:
brainly.com/question/24050043