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Illusion [34]
3 years ago
14

What is the scale factor a model car if the scale is 1 inch= 2 ft?

Mathematics
1 answer:
kodGreya [7K]3 years ago
6 0
I'm pretty sure it's 24.
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The image of (-6,6) after a dilation by a scale factor of 5 centered at the<br> а
Setler79 [48]
Answer is (24,-24)

Explanation:
Dilation centered at the origin multiplies each coordinate by the dilation factor.
image= 4(6,-6)
image= (24,-24)
8 0
2 years ago
Write each number in scientific notation, please. For 15 points!
Westkost [7]

<span>In a scientific notation, you have to put a decimal right after the first number (unless it is a zero). How many times you move the decimal from its original spot determines the answer. (FYI: In a number like 196 the decimal point is 196.000<--here)</span>

<span /><span>1.
5.8927 (moved the decimal point 4 times, so the answer is --->)  5.8927×10^{4}</span>

<span>2.
1.304×</span><span>10^{9}</span>

<span>3.
6.73×10^{6}</span>

<span>4.
1.33×10^{4}</span>

<span>5.
9.77×10^{22}</span>

<span>6.
3.84×10^{5}
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3 0
3 years ago
Which unit of measure would be appropriate for the volume of a cylinder tha
Viefleur [7K]
The unit measure that is appropriate would be Cubic meters
8 0
2 years ago
PLEASE HURRY<br><br> What is 7 7/15 as a decimal?
N76 [4]

Answer:

7/15 is 0.4667 in decimal form

Step-by-step explanation:

5 0
3 years ago
The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

P(X>3417) =0.0166

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0
3 years ago
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