Answer:
a) 1/2 red, 1/2 pink; b) all pink; c) 1/4 red, 1/2 pink, 1/4 white; d) 1/2 white, 1/2 pink
Explanation:
The flower color trait in snapdragons shows incomplete dominance: the heterozygous genotype produces an intermediate phenotype between the two different homozygous genoytpes.
<u>The possible genotypes and phenotypes are:</u>
- R1R1 : red
- R1R2: pink
- R2R2: white
<h3>a. R1R1 X R1R2
</h3>
The R1R1 individual only produces R1 gametes. The R1R2 parent produces 1/2 R1 gametes and 1/2 R2 gametes.
<u>For that reason, the F1 will be:</u>
- 1/2 R1R1 (red)
- 1/2 R1R2 (pink)
<h3>b. R1R1 X R2R2
</h3>
The R1R1 individual only produces R1 gametes. The R2R2 parent only produces R2 gametes.
<u>For that reason, the F1 will be</u> :
<h3>c. R1R2 X R1R2
</h3>
Both parents are heterozygous. This is a monohybrid cross, and from Mendel's Laws <u>we expect the following offspring:</u>
- 1/4 R1R1 (red)
- 2/4 R1R2 (pink)
- 1/4 R2R2 (white)
<h3 /><h3>d. R1R2 X R2R2</h3>
The R1R2 parent produces 1/2 R1 gametes and 1/2 R2 gametes. The R2R2 individual only produces R2 gametes.
<u>For that reason, the F1 will be:</u>
- 1/2 R2R2 (white)
- 1/2 R1R2 (pink)
Answer:
Here you go
Explanation:
Photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy. During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds.
The scientific name is Tyto alba
0.36
Explanation:
For the recessive trait to show in the phenotype, the individual has to be homozygous recessive for the gene. Therefore if we designate the allele for White color as <em>r</em> and that of Brown as <em>R</em>;
<em>rr </em>= 16% = 0.16 → This is the gene frequency for recessive population
To find the allele frequency
√0.16
= 0.4
Remember the hardy Weinberg principle of allele; All allelic frequency of a gene adds up to 1 in an ideal population (that observes certain assumptions).
p + q = 1
p + 0.4 = 1
p = 1 – 0.4
p = 0.6
The allelic frequency of Brown hair is 0.6.
The frequency of individuals of a homozygous dominant genotype will be;
P² + 2pq + q² = 1
0.6 * 0.6 = 0.36
Learn More:
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Answer: Energy flows from producers to one or more levels of consumers.
