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Kobotan [32]
3 years ago
5

(04.04)Marcus spent 10 hours doing his homework last week. This week he spent 11 hours doing homework. He says that he spent 110

% more time doing homework this week. Is he correct? Show your work to justify your decision.
Mathematics
1 answer:
IRINA_888 [86]3 years ago
4 0
I think the answer is no
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]7. A zucchini plant in Darnell’s garden was 13 centimeters tall when it was first planted. Since then, it has grown approximate
Pani-rosa [81]

Let d be the number of days and h be the height

h = 13 + 0.6d


Answer: (a) h = 13 + 0.6d


Given height = 0.208m, find d:


0.208m = 20.8 cm


20.8 = 13 + 0.6d

0.6d = 20.8 - 13 = 7.8

d = 7.8 ÷ 0.6 = 13


Answer: (b) 13 days






5 0
3 years ago
What is the volume of thiss figure ?
allochka39001 [22]

Answer:

18 ft³

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Brad had a yard that he wants to fence. The dimensions of the yard are 40 feet by 55 feet. How much fencing would he need to enc
natta225 [31]
2(40+55)=2(95)=190
190ft of fencing
4 0
3 years ago
The circumference of the equator of a sphere was measured to be 82 82 cm with a possible error of 0.5 0.5 cm. Use linear approxi
True [87]

Answer:

The maximum error in the calculated surface area is approximately 8.3083 square centimeters.

Step-by-step explanation:

The circumference (s), in centimeters, and the surface area (A_{s}), in square centimeters, of a sphere are represented by following formulas:

A_{s} = 4\pi\cdot r^{2} (1)

s = 2\pi\cdot r (2)

Where r is the radius of the sphere, in centimeters.

By applying (2) in (1), we derive this expression:

A_{s} = 4\pi\cdot \left(\frac{s}{2\pi} \right)^{2}

A_{s} = \frac{s^{2}}{\pi^{2}} (3)

By definition of Total Differential, which is equivalent to definition of Linear Approximation in this case, we determine an expression for the maximum error in the calculated surface area (\Delta A_{s}), in square centimeters:

\Delta A_{s} = \frac{\partial A_{s}}{\partial s} \cdot \Delta s

\Delta A_{s} = \frac{2\cdot s\cdot \Delta s}{\pi^{2}} (4)

Where:

s - Measure circumference, in centimeters.

\Delta s - Possible error in circumference, in centimeters.

If we know that s = 82\,cm and \Delta s = 0.5\,cm, then the maximum error is:

\Delta A_{s} \approx 8.3083\,cm^{2}

The maximum error in the calculated surface area is approximately 8.3083 square centimeters.

6 0
3 years ago
Please answer 5,6,7. With explanation.
Anestetic [448]
First you need to know some rules 2 numbers that are the same with coefficients divided : you differentiate those coeff
and multyplied :you sum up them

12x^8/3x^3= 4x^8-3=4x^5

20^2x=20^x*20^x

m^5*m^-7=m^5-7=m^-2







8 0
4 years ago
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