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Nonamiya [84]
3 years ago
7

Simplify by combining like terms: -3 + 6x - 18 - 22x

Mathematics
2 answers:
alekssr [168]3 years ago
8 0
Answer: -16x-21

Explanation: 6x + (-22x)=-16x
-18+(-3)=-21
Illusion [34]3 years ago
3 0
You Are going to first identify which numbers are similar to another.
-3, -18
6x, -22x
Start with the variables: 6x -22x
Which is -16x
Next combine the other numbers: -3-18
Which is -21
Finally you put together your 2 Answers together: -16x-21 or -21-16x
Hope this helps. You will use the sale method when combining like terms with an equal sign and multiple numbers and variables.
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A model rocket is launched with an intitial upupward velocity of 202 ft/s. The rocket’s height h (in feet) after seconds is give
dsp73

Given that the height of a object thrown within a gravitational field is given as a quadratic equation in time, <em>t</em>, the time at which the object is at a specified height can be found by the quadratic formula

The values of, <em>t</em>, for which the height of the rocket is 82 feet are;

t = 12.21 seconds or t = 0.42 seconds

Question: <em>Parts of the question that appear missing but can be found online are (i) To find the values of the time, t, when the rocket's height is 82 feet and round answers to the nearest hundredth</em>

The known parameters of the rocket are;

The initial upward velocity of the rocket, v = 202 ft./s

The given function representing the height, <em>h</em>, (in feet) after <em>t</em> seconds is presented as follows;

H = 202·t - 16·t²

The unknown;

The time for which the height of the rocket is 82 feet

Method;

Substitute H = 82 feet in the height function equation and solve for <em>t</em> as follows;

When H = 82, we get;

82 = 202·t - 16·t²

Therefore;

16·t² - 202·t + 82 = 0

Dividing the above equation by <em>2</em> gives;

(16·t² - 202·t + 82)/2 = 0/2

8·t² - 101·t + 41 = 0

By using the quadratic formula, we get;

\mathbf{t = \dfrac{101 \pm \sqrt{(-101)^2 - 4 \times 8 \times 41} }{2 \times 8}  =  \dfrac{101 \pm \sqrt{8889} }{16}}

Therefore, the values of <em>t</em> given by rounding off to the nearest hundredth are;

t = 12.21 or t = 0.42

The values of the time, <em>t</em>, at which the height of the rocket is 82 feet are t = 12.21 seconds or t = 0.42 seconds

Learn more about equation models of height as a function of time here;

brainly.com/question/84352

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3 years ago
F(1) = 4, f(n) = (−9) · f(n − 1) + 18
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f,n=4 and 27/20

this is the answer


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3 years ago
Tim needs 18 pens he can buy them in packages of 6 9 or 12 he will buy only one type of package which packages could Tim buy wri
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Answer:

See below.

Step-by-step explanation:

Either 3 packets of 6 pens  or

2 packets of 9 pens.

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3 years ago
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Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
WITCHER [35]

Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

Step-by-step explanation:

Given,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

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f_x=yz,f_y=xz,f_z=xy+6z

Integrating f_x we get,

f(x,y,z)=xyz+g(y,z)

Differentiate this with respect to y we get,

f_y=xz+g'(y,z)

compairinfg with f_y=xz of the given function we get,

g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)

Then,

f(x,y,z)=xyz+h(z)

Again differentiate with respect to z we get,

f_z=xy+h'(z)=xy+6z

on compairing we get,

h'(z)=6z\implies h(z)=3z^2+C   (By integrating h'(z))  where C is integration constant. Hence,

f(x,y,z)=xyz+3z^2+C

(b) Next, to find the itegration,

\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

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