Answer:
Step-by-step explanation:
y = sin(t^2)
y' = 2tcos(t^2)
y'' = 2cos(t^2) - 4t^2sin(t^2)
so the equation become
2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0
when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.
Answer/Step-by-step explanation:
A) The temperature in Chicago could be -10*F because -10 is to the right of -13 on the number line.
Higher Temperatures -->
o----------->I
I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I
-13 -12 -11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10
Answer:
is the answer. See steps below.
Step-by-step explanation:
Repeat the steps and you will reach a point where no further division is possible.
<u />
<u />
<u />
Answer:
y=10x
Step-by-step explanation:
