The equation y−4=-3(x−2) is in point-slope form. which is the slope-intercept form of the equation?

How many times does X squared minus 4X -12 cross the X axis

kolbaska11 [484]

We can solve this problem using discriminant.

x^2-4x-12's discriminant is

(-4)^2-4*-12=16+48 which is clearly larger than 0

This means that it crosses over the axes 2 times.

In case you don't know what discriminant is, its in equation ax^2+bx+c

the discriminant is b^2-4ac.

If its positive it has 2 crosses with x axis, if negative then 0 crosses, if 0 then 1 cross.

Hope this helped at least a little bit :D

4 0

2 years ago

Mallory works 20 hours a week as a website designer and earns $42.50 per hour. If Mallory saves

AleksandrR [38]

If Mallory makes $42.50 per hour and she works 20 hours a week, we multiple those two and we get:

42.5 * 20 = 850

So she earns $850 per week.

Mallory saves half of that amount she would have $425 per week.

In 4 weeks she would have:

425 * 4 = 1700

Mallory will save $1,700 in four weeks.

3 0

3 years ago

Read 2 more answers

What is the denominator of 7/9

Lina20 [59]

Answer:

9

Step-by-step explanation:

The denominator of a fraction is always the bottom number, while the top number is always the numerator.

5 0

3 years ago

Read 2 more answers

If 0 is a positive acute angle and 2 cos 0+3 = 4,<br> find the number of degrees in 0.

Lemur [1.5K]

Answer: 1 0 is like x you solve for x. X= 1 0=1

4 0

3 years ago

A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores

EastWind [94]

Answer:

$(52-49) -4.300= -1.300$

$(52-49) +4.300= 7.300$

And the 95% confidence would be :

$-1.300 \leq \mu_1 -\mu_2 \leq 7.300$

Step-by-step explanation:

We have the following info given from the problem

$\bar X_1 = 52$ sample mean for this year

$s_1= 13$ sample deviation for this year

$n_1 = 75$ random sample selected for this year

$\bar X_2 = 49$ sample mean for last year

$s_2= 11$ sample deviation for last year

$n_1 = 53$ random sample selected for last year

And we want to construct a 95% confidence interval estimate of the difference μ1−μ2, where μ1 is the mean of this year's sales and μ2 is the mean of last year's sales

For this case the formula that we need to use is:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$