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arsen [322]
3 years ago
14

Write the equation that shows the relationship in the table

Mathematics
1 answer:
GenaCL600 [577]3 years ago
8 0

Answer:

y= 20x

Step-by-step explanation:

40/2=100/5=200/10=20  linear function.

I hope this help you

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4 years ago
the diagram shows 3 identical circles inside a rectangle. each circle touches the other two circles and the sides of the rectang
Sergio [31]

Answer:

2640mm

Step-by-step explanation:

I'm assuming you need the area of the rectangle which the circles don't take up.

First, to find the area of the whole rectangle:

length x width

to find length:

the length is 1 circle, therefore it is the diameter of the circle, which is 32 x 2 = 64mm

to find width:

the width is 3 circles, which is the radius 6 times, so 32 x 6 = 192mm

So, area of rectangle = 64 x 192 = 12288mm

Now to find the area the circles take up:

area of 1 circle =

\pi \times  {r}^{2}

=

\pi \times  {32}^{2}

=

1024\pi

As we have 3 circles, we multiply this by 3:

1024\pi \times 3 = 3072\pi

Finally we subtract the area of the three circles from the area of the rectangle:

12288mm - 3072\pi = 2637

As we need to round it to 3 significant figures, the answer is 2640mm

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2 years ago
Question 5(Multiple Choice Worth 5 points)
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Answer:

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The Royal Fruit Company produces two types of fruit drinks. The first type is
Dimas [21]
Now, the percentage figures of say, 70%, 95% and so on, we'll use the decimal format of the, thus 70% is just 70/100 or 0.7 and 95% is just 95/100 or 0.95 and so on

so  \bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentration\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{70\% pure}&x&0.7&0.7x\\
\textit{95\% pure}&y&0.95&0.95y\\
-----&-----&-------&-------\\
mixture&160&0.85&(160)(0.85)
\end{array}

whatever "x" and "y" amounts are, we know, they must add up to 160 pints
thus  x + y = 160

now, whatever the concentrated amount of solute in the mixture, we know they must add up to 160*0.85 or 136

thus   0.7x + 0.95y = 136

thus    \bf \begin{cases}
x+y=160\implies \boxed{y}=160-x\\
0.7x+0.95y=136\\
----------\\
0.7x+0.95\left( \boxed{160-x} \right)=136
\end{cases}

solve for "x", to see how much of the 70% pure juice will be needed

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3 years ago
What is the value of the expression when p = -24 and q= 4?
Sophie [7]
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