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dimulka [17.4K]
4 years ago
9

Find three different pairs of fractions which multiply to 25/32.​

Mathematics
1 answer:
Alex_Xolod [135]4 years ago
6 0

Answer:

Step-by-step explanation:

5/8*5/4=25/32

1/16*25/2=25/32

25/16*1/2=25/32

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Using the equation y = 2x + 5, what would the input need to be for an output of -15?
vfiekz [6]

Answer:

x = -10

Step-by-step explanation:

y = 2x + 5

-15 = 2x + 5

-20 = 2x

-10 = x

4 0
3 years ago
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Which of the following is an example of a nonterminating, nonrepeating decimal?
BARSIC [14]

Answer:

Option B. 0.578942190874654...

Step-by-step explanation:

we know that

A non-terminating, non-repeating decimal is a decimal number that continues endlessly, with no group of digits repeating endlessly

example

the number \pi= 3.1415926535...

In this problem

the number 0.578942190874654... is a non-terminating, non-repeating decimal

5 0
3 years ago
The length of time it takes to find a parking space at 9 A.M. follows a normal distribution with a mean of 5 minutes and a stand
erastovalidia [21]

Answer:

z=0.524

And if we solve for a we got

a=5 +0.524*2=6.048 \approx 6.05 min

Step-by-step explanation:

Let X the random variable that represent the lenght time it takes to find a parking space at 9AM of a population, and for this case we know the distribution for X is given by:

X \sim N(5,2)  

Where \mu=5 and \sigma=2

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.3   (a)

P(X   (b)

As we can see on the figure attached the z value that satisfy the condition with 0.7 of the area on the left and 0.3 of the area on the right it's z=0.524

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.524

And if we solve for a we got

a=5 +0.524*2=6.048 \approx 6.05 min

3 0
3 years ago
The quadratic formula gives which roots for the equation 2x^2 + x - 6 = 0?
Jet001 [13]

Answer:

The roots are x = (\frac{3}{2}, -2), which is given by option C.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question, we have that:

2x^2 + x - 6 = 0

Which is a quadratic equation with a = 2, b = 1, c = -6. So

\Delta = 1^{2} - 4*2(-6) = 1 + 48 = 49

x_{1} = \frac{-1 + \sqrt{49}}{2*2} = \frac{6}{4} = \frac{3}{2}

x_{2} = \frac{-1 - \sqrt{49}}{2*2} = \frac{-8}{4} = -2

So the roots are x = (\frac{3}{2}, -2), which is given by option C.

3 0
3 years ago
If i have a silver necklece at the price of 26 $ and its 50 percent of what was the orginal price.
amid [387]

50%=100%/2

26*2 = 52

Original price is 52 dollas

6 0
3 years ago
Read 2 more answers
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