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dimulka [17.4K]
3 years ago
9

Find three different pairs of fractions which multiply to 25/32.​

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
6 0

Answer:

Step-by-step explanation:

5/8*5/4=25/32

1/16*25/2=25/32

25/16*1/2=25/32

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Miguel has 1 foot of string. He cuts the string into fourths. How many inches is each piece of string?
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Each piece of string has 3 inches each
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MARKING BRAINLEST!!!!!!!!!
lapo4ka [179]

Answer:

A  3^4 * 3^-4 / 3^6

C 1 / 3^6

Step-by-step explanation:

( 3^2 * 3^-2)

-------------------  all the the power of 2

           3^3

First simplify the numerator

We know a^b* a^c = a^(b*c)

( 3^(2+-2))

-------------------  all to the power of 2

           3^3

( 3^(0))

-------------------  all to the power of 2

           3^3

( 3^(0))

-------------------  all to the power of 2

           3^3

We know a^b/ a^c = a^(b-c)

3^(0-3)  all to the power of 2

3^-3 all to the power of 2

3^-3 ^2

We know that a^b^c = a^(b*c)

3^(-3*2)

3^ -6

We know the negative exponent takes if from the numerator to the denominator

1 / 3^6

The other correct choice is A

3^4 * 3^-4 = 3^0 which is 1

1/3^6 is the same answer

8 0
3 years ago
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Speed, Time, and Dis
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Answer:

3 hours

Step-by-step explanation:

Recall:

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we are given that speed = 18 km/h and distance = 54 km.

hence,

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The length of a rectangle is three inches more than the width. the area of the rectangle is 180 inches. find the width of the re
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We have a rectangle with length L that is 3 inches more than the width W. Then we can write this as:

L=W+3

The area of the rectangle is 180 square inches.

We have to find the width W.

As the area is equal to the product of the length and the width, we can write this equation and solve for W as:

\begin{gathered} A=180 \\ L\cdot W=180 \\ (W+3)\cdot W=180 \\ W^2+3W=180 \\ W^2+3W-180=0 \end{gathered}

We have a quadratic equation. The roots of this equation will be the mathematical solutions.

We can find the roots using the quadratic formula:

\begin{gathered} W=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ W=\frac{-3\pm\sqrt[]{3^2-4\cdot1\cdot(-180)}}{2\cdot1} \\ W=\frac{-3\pm\sqrt[]{9+720}}{2} \\ W=\frac{-3\pm\sqrt[]{729}}{2} \\ W=\frac{-3\pm27}{2} \\ W_1=\frac{-3-27}{2}=-\frac{30}{2}=-15 \\ W_2=\frac{-3+27}{2}=\frac{24}{2}=12 \end{gathered}

The solutions are W = -15 and W = 12.

The first one is not valid, as W has to be greater than 0.

Then, the solution to our problem is W = 12 in.

Answer: the width is W = 12 inches.

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What is the approximate value of sin B?
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the answer is A. 0.92

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