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SVETLANKA909090 [29]
3 years ago
13

How do i find the area of a trapezoid (pictures provided)

Mathematics
1 answer:
scoray [572]3 years ago
5 0

Answer:

(10x - 5) square units.

Step-by-step explanation:

Let the lengths of equal sides be x units.

Hence, AB + AD + DC = x + x + x = 3x

Therefore, BC = 3x - 2

Area  \: of \:  trapezoid  \\ =  \frac{1}{2} (AD + BC)  \times 5 \\  = \frac{1}{2} (x + 3x - 2)  \times 5  \\ = \frac{1}{2} (4x - 2)  \times 5  \\ = \frac{1}{2} \times 2 (2x - 1)  \times 5  \\  = (2x - 1) \times 5 \\  = (10x - 5) \:  {units}^{2}

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ASAP PLS!! i attached a link with a screenshot of the question. please give step by step!!!!! will mark brainliest :)
emmainna [20.7K]

Answer:

I found two different solutions. Hope one of them help!

1. x = -1/3 = -0.333

2. x = 5/2 = 2.500

Step-by-step explanation:

13 ± √ 289

  x  =    ——————

                     12

Can  √ 289 be simplified ?

Yes!   The prime factorization of  289   is

  17•17

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 289   =  √ 17•17   =

               ±  17 • √ 1   =

               ±  17

So now we are looking at:

          x  =  ( 13 ± 17) / 12

Two real solutions:

x =(13+√289)/12=(13+17)/12= 2.500

or

x =(13-√289)/12=(13-17)/12= -0.333

Two solutions were found :

x = -1/3 = -0.333

x = 5/2 = 2.500

7 0
3 years ago
Your savings account pays 1.75% interest per year. You make a $500 deposit. How much interest does the account earn in the first
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Answer:

Step-by-step explanation:

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Answer:

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