Question

How do i find the area of a trapezoid (pictures provided)

Answer 1

Answer:

(10x - 5) square units.

Step-by-step explanation:

Let the lengths of equal sides be x units.

Hence, AB + AD + DC = x + x + x = 3x

Therefore, BC = 3x - 2

$Area \: of \: trapezoid \\ = \frac{1}{2} (AD + BC) \times 5 \\ = \frac{1}{2} (x + 3x - 2) \times 5 \\ = \frac{1}{2} (4x - 2) \times 5 \\ = \frac{1}{2} \times 2 (2x - 1) \times 5 \\ = (2x - 1) \times 5 \\ = (10x - 5) \: {units}^{2}$