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Evgen [1.6K]
3 years ago
12

The alphabet of a fictionary tribe consists of three letters: A, O and M. Any combination of no more than four of these letters

is considered a word. How many words are does this tribe's language have?
Mathematics
1 answer:
andrezito [222]3 years ago
8 0

Answer:

120 words

Step-by-step explanation:

There are only three possible letters, assuming words can be 1, 2, 3 or 4 letters long:

The number of 1 letter words is 3

The number of 2 letter words is 3² = 9

The number of 3 letter words is 3³ = 27

The number of 4 letter words is 3⁴ = 81

The total number of possible words is:

3+9+27+81 = 120\ words

This tribe's language has 120 words.

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Maurinko [17]

Answer:

\frac{23913}{25000}

Step-by-step explanation:

According to the Order of Operations [GEMS\BOMDAS\PEMDAS etc.], Subtraction & Addition are evaluated after Division & Multiplication:

2 + 6 \times 3000001 \div 23 - 2 + 1 \\  \\ 2 + 782608\frac{1913}{2000} - 2 + 1 = \frac{23913}{25000}

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3 years ago
(8 points)
Harman [31]

Answer:

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Step-by-step explanation:

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2 years ago
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noname [10]

Answer:

Love encompasses a range of strong and positive emotional and mental states, from the most sublime virtue or good habit, the deepest interpersonal affection, to the simplest pleasure.

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7 0
3 years ago
What does y equal ??!?!
garik1379 [7]
<h3>Answer:  658.3</h3>

==================================================

Explanation:

The adjacent complementary angle to that 28 degree angle is 62 degrees because 62+28 = 90.

If the reference angle is the upper acute angle 62 degrees, then the y is the opposite leg and the side 350 is the adjacent leg.

Use the tangent ratio

tan(angle) = opposite/adjacent

tan(62) = y/350

350*tan(62) = y

y = 350*tan(62)

y = 658.254262871217

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3 0
3 years ago
Read 2 more answers
A sheet of paper 90 cm-by-66 cm is made into an open box (i.e. there's no top), by cutting x-cm squares out of each corner and f
NNADVOKAT [17]

Answer:

26 - \sqrt{181} cm

Step-by-step explanation:

The volume of the box is:

V = height * length * width

V = x*(66 - 2*x)*(90 - 2*x)

V = (66*x - 2*x^2)*(90 - 2*x)

V = 5940*x - 132*x^2 - 180*x^2 + 4*x^3

V = 4*x^3 - 312*x^2 + 5940*x

where x is the length of the sides of the squares,  in cm.

The mathematical problem is :

Maximize: V = 4*x^3 - 312*x^2 + 5940*x

subject to:

x > 0

2*x < 66 <=> x < 33

In the maximum, the first derivative of V, dV/dx, is equal to zero

dV/dx = 12*x^2 - 624*x + 5940

From quadratic formula

x = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}

x = \frac{624 \pm \sqrt{(-624)^2 - 4(12)(5940)}}{2(12)}

x = \frac{624 \pm \sqrt{104256}}{24}

x = \frac{624 \pm \sqrt{2^6*3^2*181}}{24}

x = \frac{624 \pm 8*3*\sqrt{181}}{24}

x_1 = \frac{624 + 24*\sqrt{181}}{24}

x_1 = 26 + \sqrt{181}

x_2 = \frac{624 - 24*\sqrt{181}}{24}

x_2 = 26 - \sqrt{181}

But x_1 > 33, then is not the correct answer.

5 0
3 years ago
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