For the point P(−19,18) and Q(−14,23), find the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ.
Cos x = -12/13
sin x = -sqrt(13^2 - 12^2) / 13 = -5/13
tan x = 5/12
tan x/2 = (1 - cos x) / sin x = 1 - (-12/13) / -5/13 = 25/13 * -13/5 = -5
2sin^2 x/2 = 1 - cos x = 1 - (-12/13) = 25/13
sin^2 x/2 = 25/13 / 2 = 25/26
sin x/2 = 5/√26
sin x/2 / cos x/2 = tan x/2
cos x/2 = sin x/2 / tan x/2 = 5/√26 / -5 = -1/√26
sin x/2 = 5/√26
cos x/2 = -1/√26
tan x/2 = -5
Answer:
x = 22 degrees
Step-by-step explanation:
Since this is a right angle and both angles added together will equal to 90degrees this means that:
(3x-5) + (x+7) = 90
(first, remove the brackets)
3x-5+x+7 = 90
( add the numbers together and the term x together)
( 3x+x ) + ( -5+7 ) = 90
4x + 2 = 90
(subtract 2 from both sides)
4x = 88
(divide by 4 from both sides)
x = 22
so the measure of x = 22 degrees
Answer:
Acute triangle
Step-by-step explanation:
If you add up are those angle equations, set it equal to 0, 26x - 2 = 180, you get x = 7/ Plug that back into each equation, and you realize none of the angles are more than 90. This makes it an acute triangle.
By giving just the radius and asking for the arc length of that circle your answer will be without math is 22
π
feet
But;
Let’s do same math!
Arc length = (()/360)⋅2⋅⋅
(
(
a
n
g
l
e
o
f
a
r
c
)
/
360
)
⋅
2
⋅
π
⋅
r
In this case angle of arc was not specified so: 360∘
∘
was used.
Arc length = ((360)/360)⋅2⋅⋅11
(
(
360
)
/
360
)
⋅
2
⋅
π
⋅
11
Arc length = 22
π
feet
