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Galina-37 [17]
3 years ago
14

Gabrielle took a Spanish test with 50 questions and answered 44 of them correctly. What percent of the questions did Gabrielle a

nswer correctly?
Mathematics
2 answers:
Ivenika [448]3 years ago
8 0

Gabrielle took a Spanish test with 50 questions. She answered 50 questions but only answered 44 of them correctly. What percent of the questions did Gabrielle answer correctly?

The fraction \frac{44}{50} represents the 44 questions that Gabrielle got correct out of the 50 questions she answered altogether.

To find out what percent of questions Gabrielle answered correctly, we can turn \frac{44}{50} into a percent.

We can first reduce the fraction \frac{44}{50} by dividing both the numerator and denominator by the Greatest Common Factor of 44 and 50 using 2.

44 ÷ 2 = 22

50 ÷ 2 = 25

22 ÷ 25 = 0.88

0.88 × 100 = 88%

Therefore, Gabrielle answered 88% percent of the questions correct on her Spanish test.

mrs_skeptik [129]3 years ago
7 0
She answered 88% correct. 44 times 2 is 88.
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Mark A machine has two parts labeled A and B. The probability that part A works for one year is 0.8 and the probability that par
Mrrafil [7]

Answer:

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

The probability that part A works for one year is 0.8 and the probability that part B works for one year is 0.6.

This means that P(A) = 0.8, P(B) = 0.6

The probability that at least one part works for one year is 0.9.

This means that: P(A \cup B) = 0.9

We also have that:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

0.9 = 0.8+0.6 - P(A \cap B)

P(A \cap B) = 0.5

Calculate the probability that part B works for one year, given that part A works for one year.

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.5}{0.8} = 0.625

0.625 = 62.5% probability that part B works for one year, given that part A works for one year.

3 0
2 years ago
Suppose we are interested in analyzing the weights of NFL players. We know that on average, NFL players weigh 247 pounds with a
Diano4ka-milaya [45]

Answer:

a) The standard error would be of 8.58 pounds.

b) The margin of error is 14.11 pounds.

c) The 90% confidence interval for the population mean is between 232.89 pounds and 261.11 pounds

Step-by-step explanation:

a.What is the standard error?

The standard error is

s = \frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample. So

s = \frac{47}{\sqrt{30}} = 8.58

The standard error would be of 8.58 pounds.

b.What is the margin of error at 90% confidence?

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find the margin of error M as such

M = z*s = 1.645*8.58 = 14.11

The margin of error is 14.11 pounds.

c. Using my sample of 30, what would be the 90% confidence interval for the population mean?

Lower bound: Sample mean subtracted by the margin of error.

247 - 14.11 = 232.89 pounds

Upper bound

247 + 14.11 = 261.11 pounds

The 90% confidence interval for the population mean is between 232.89 pounds and 261.11 pounds

4 0
3 years ago
If you inflate a beach ball with 14,130 cubic inches of air, what will its radius be? Use 3.14 for π. Round to the nearest whole
GREYUIT [131]

Answer: 15

Step-by-step explanation:

The answer is because if you divide 14,130 by 3.14. You'll get 4500 and then divide that by 300 and your finally is 15

8 0
2 years ago
Suppose Casey Title Company normally charges $300 for services related to selling a house. As part of a summer special, Casey of
g100num [7]

Given :

Casey's company charges , C = $300.

In summer special, Casey offers customers a trade discount of 25%.

To Find :

Charges during summer.

Solution :

Let, x is the amount of charges they take during summer.

Casey offers customers a trade discount of 25%.

x =300(1-\dfrac{25}{100})\\\\x=300(1 - 0.25)\\\\x=300(0.75)\\\\x=\$225

Therefore, amount of charges during summers are $225.

Hence, this is the required solution.

8 0
2 years ago
Use the order of operations to find the value of the expression. 2 + 3 × 16 − 2 × 21 − 3
kolezko [41]

Answer:

5

Step-by-step explanation:

=2+(3)(16)-(2)(21)-3

=2+48-(2)(21)-3

=50-(2)(21)-3

=50-42-3

=8-3

=5

Hope this helped! :)

6 0
2 years ago
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