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Bad White [126]
3 years ago
13

3(x - 2) = 12show how you would solve plz​

Mathematics
2 answers:
Yakvenalex [24]3 years ago
8 0

Answer: x=6

Step-by-step explanation:

3(x-2)=12

3x-6=12

3x=18

x=6

MrMuchimi3 years ago
4 0

Answer:

x = 6

Step-by-step explanation:

3(x - 2) = 12

3x - 6 =   12

    +6 =   +6

3x     =   18

÷ 3     =  ÷3

  x     =   6

<em>Hope this helps</em>

<em>-Amelia</em>

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You divide 1444 kilometers by 110 kilometers to get x cm.

1444/110 = <span>13.127

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5 0
3 years ago
Find the distance between the points.<br> (0,4) and (-3,4)<br> The distance is
Inessa [10]
<h3>Answer:  3 units</h3>

=============================================================

Explanation:

The y coordinates are identical, so we just need to focus on the x coordinates.

Going from 0 to -3 is a distance of 3 units. Drawing out a number line might help.

Or we could apply subtraction and absolute value

|x1-x2| = |0-(-3)| = |0+3| = |3| = 3

which is the same as

|x2-x1| = |-3-0| = |-3| = 3

The absolute value is to ensure the result is never negative. Distance is never negative.

Side note: if the y coordinates weren't the same, then we'd have to use either the pythagorean theorem or the distance formula.

4 0
3 years ago
The sum of two consecutive integers is 139, find the integers.
Ad libitum [116K]
They would be 69 and 70.

Your equation would be x + (x + 1) = 139

X would be the first integer and x + 1 would be the second

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X + 1 would then be 70
7 0
3 years ago
How do you divide decimals?
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3 0
4 years ago
HELP 40 POINTS
Tom [10]
Answer: the function g(x) has the smallest minimum y-value.


Explanation:


1) The function f(x) = 3x² + 12x + 16 is a parabola.


The vertex of the parabola is the minimum or maximum on the parabola.


If the parabola open down then the vertex is a maximum, and if the parabola open upward the vertex is a minimum.


The sign of the coefficient of the quadratic term tells whether the parabola opens upward or downward.


When such coefficient is positive, the parabola opens upward (so it has a minimum); when the coefficient is negative the parabola opens downward (so it has a maximum).


Here the coefficient is positive (3), which tells that the vertex of the parabola is a miimum.


Then, finding the minimum value of the function is done by finding the vertex.

I will change the form of the function to the vertex form by completing squares:

Given: 3x² + 12x + 16

Group: (3x² + 12x) + 16
Common factor: 3 [x² + 4x ] + 16
Complete squares: 3[ ( x² + 4x + 4) - 4] + 16
Factor the trinomial: 3 [(x + 2)² - 4] + 16
Distributive property: 3 (x + 2)² - 12 + 16
Combine like terms: 3 (x + 2)² + 4

That is the vertex form: A(x - h)² + k, whch means that the vertex is (h,k) = (-2, 4).


Then the minimum value is 4 (when x = - 2).


2) The othe function is <span>g(x)= 2 *sin(x-pi)
</span>

The sine function goes from -1 to + 1, so the minimum value of sin(x - pi) is - 1.


When you multiply by 2, you just increased the amplitude of the function and obtain the new minimum value is 2 (-1) = - 2


Comparing the two minima, you have 4 vs - 2, and so the function g(x) has the smallest minimum y-value.

7 0
4 years ago
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