2 years ago

What is the slope of a line that passes through (2,-5) and (6,-2)

Mathematics

1 answer:

andrey2020 [161]2 years ago

7 0

Answer:

$\frac{3}{4}$

Step-by-step explanation:

You plug in the points in this equation $\frac{y2-y1}{x2-x1}$

So $\frac{-2-(-5)}{6-2}$ = $\frac{3}{4}$

You might be interested in

Find the length of BC.

Murrr4er [49]

Answer:

C, 53.68 units

Step-by-step explanation:

tan 54° = $\frac{x}{39}$

39 tan 54° = x

x= 53.6788949 (just plug it in a scientific or graphing calculator)

x≈53.68

4 0

2 years ago

Find the equation of the line that passes through he points (2,6) and (-2,4)

stepan [7]

First Find slope by using $\frac{y2-y1}{x2-x1}$

$\frac{4-6}{-2-2} = \frac{-2}{-4} = \frac{1}{2}$

Now use point Slope form to find the equation of the line (y-y₁)=m(x-x₁)
(y-6)= $\frac{1}{2}$ (x-2)
y-6= $\frac{1}{2} x-1$
y= $\frac{1}{2} x+5$ is your equation