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galina1969 [7]
3 years ago
7

Find a numerical value of one trigonometric function of x for cos^2x+2sinx-2=0

Mathematics
2 answers:
quester [9]3 years ago
8 0

Answer:

\sin x=1

Step-by-step explanation:

The given function is

\cos^2x+2\sin x-2=0

We use the identity: \sin^2x+\cos^2x=1 \implies \cos^2x=1-\sin^2x

This implies that:

1-\sin^2x+2\sin x-2=0

-\sin^2x+2\sin x-1=0

\sin^2x-2\sin x+1=0

(\sin x-1)^2=0

\sin x-1=0

\sin x=1

Hence the numerical value of one trigonometric function(the sine function) is 1

Sergeu [11.5K]3 years ago
4 0

Answer:

Step-by-step explanation:

From

\cos^2x+2\sin x-2=0

Using the identity, we have: \sin^2x+\cos^2x=1 \implying \cos^2x=1-\sin^2x

Opperating:

1-\sin^2x+2\sin x-2=0

-\sin^2x+2\sin x-1=0

\sin^2x-2\sin x+1=0

(\sin x-1)^2=0

\sin x-1=0

\sin x=1

A numerical value for x would be for example x=90 degrees or pi/2 (radians)

And this answer is valid for every angle x=90+360n (n=0,1,2,3,etc) or x=pi/2+2pi*n (n=0,1,2,3,etc)

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In 2000, Canada produced 3.0 million new motor vehicles. In 2006, it produced 2.5 million. Write the linear equation (in slope-i
kogti [31]
To begin, you are given two point that this function would intercept: (0,3) where the 0 is the original year (2000) and 3 is the amount of million cars sold. The next point would be (6,2.5) Where the 6 is the 6 years later and the 2.5 is the 2.5 million cars sold. Since we have 2 points, we can work out the gradient by finding the rate of change in y and dividing by the rate of change in x:
\frac{y_{1}- y_{2}  }{x_{1}- x_{2} }

We then substitute in the points:
x_{1} =3
y_{1} =0
x_{2} =2.5
y_{2} =6

\frac{3-2.5}{0-6}
=\frac{0.5}{-6}
=-.083

Because we started on the y-intercept of (0,3), we already have our intercept value of 3. If we did not start with the y-intercept given, we could substitute in a point to solve for it:

Using point (2.5,6):

<span>2.5=-0.083*6+c
</span>2.5=-0.5+c
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Hope this helps :)




5 0
3 years ago
List two pairs of fractions with a product of 6/40
puteri [66]

Answer:

The product of two fractions can be calculated as follows:

\frac{a}{b}\cdot \frac{c}{d}=\frac{a \cdot c}{b \cdot d}

So, the numerator is the product of the numerators of the two fractions, and the denominator is the product of the denominators of the two fractions.

In this problem, we know that the product is 6/40, so:

ac = 6\\bd = 40

This means:

c=\frac{6}{a}\\d=\frac{40}{b}

So we just need to find 2 pairs of numbers a, b to make c and d integers.

The first choice we use is:

a = 3

b = 2

So we get:

c=\frac{6}{3}=2\\d=\frac{40}{2}=20

So the first pair of fractions is

\frac{3}{2},\frac{2}{20}

The second choice we use is:

a = 2

b = 10

So we get:

c=\frac{6}{2}=3\\d=\frac{40}{10}=4

So the second pair of fractions is

\frac{2}{10},\frac{3}{4}

8 0
3 years ago
What is 5×6×7/19×5.898 = ?<br> 100 Points Exclusive !!!
pshichka [43]

Answer:

65.188421

Step-by-step explanation:

hope i helped<3Have a nice day and remember to drink water!

8 0
3 years ago
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2/23 yards= how many feet?
kykrilka [37]
A yard is three feet 
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that is 0.26 feet

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4 0
4 years ago
I'll mark brainiest if right answer
igomit [66]

Answer: x=2  y=18

Step-by-step explanation

3 0
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