The equation that can be used to represent the situation given that x is the number of hours spent babysitting is 4(x + 8) = 56
<h3>How to write and solve equation</h3>
- Amount paid per hour for babysitting =$4
- Total amount made = $56
- Hours spent babysitting on Sunday = 8 hours
Total earned babysitting on Sunday = Hours spent babysitting on Sunday × Amount paid per hour
= 8 × 4
= $32
Number of hours he babysat on Saturday = $56 - (8 × 4) ÷ 4
= 56 - 32 ÷ 4
= 24 ÷ 4
= 6 hours
A. 8x+4 = 56
8x = 56 - 4
8x = 52
x = 52/8
x = 6.5
B. 4x+8 = 56
4x = 56 - 8
4x = 48
x = 48/4
x = 12
C. 8(x + 4) = 56
8x + 32 = 56
8x = 56 - 32
8x = 24
x = 24/8
x = 3
D. 4(x + 8) = 56
4x + 32 = 56
4x = 56 - 32
4x = 24
x = 24/4
x = 6
Learn more about equation:
brainly.com/question/16863577
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way
Step-by-step explanation:
- From a standard deck of cards, one card is drawn. What is the probability that the card is black and a
jack? P(Black and Jack) P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
- A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen
or an ace.
P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13
- WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the probability that they will both be aces?
P(AA) = (4/52)(3/51) = 1/221.
- WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a king?
P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed.
- WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the
probability of drawing the first queen which is 4/52.
- The probability of drawing the second queen is also 4/52 and the third is 4/52.
- We multiply these three individual probabilities together to get P(QQQ) =
- P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
- Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
Answer:
34, 1.5, 9, 12, 3.6
Step-by-step explanation:
40.8/1.2=
1.8/1.2=
10.8/1.2=
14.4/1.2=
4.32/1.2=
Answer:
x+63=90(complementary angle)
x=90-63
x=27
This is true. IDK if there is a question behind it.
