All categories

4 years ago

If 3(x+2)-2(x+1)=8 the value of x is

2 answers:

andrey2020 [161]4 years ago

7 0

Use PEMDAS and the distributive property to solve this problem-
3(x+2)-2(x+1)=8
(3 times x and 3 times 2)
3x+6-2(x+1)=8
(-2 times x and -2 times 1)
3x+6-2x-2=8
Combine like terms (3x/-2x and 6/-2)
x+4=8
Subtract 4 from both sides
x=4

Citrus2011 [14]4 years ago

4 0

3(x+2)-2(x+1)=8
you distribute the 3 to the numbers inside the parentheses as well as the -2 which gives you:
3x+6-2x-2=8
then you combine like terms which gives you:
x+6-2=8
then you subtract 4 from both sides to isolate x and you end up with:
x=4
Hope this helps!

You might be interested in

What is 1024 1/5 simplified?

frutty [35]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\
1024\frac{1}{5}\qquad 
\begin{cases}
1024=2^{10}\\
\frac{1}{5}=5^{-1}
\end{cases}\implies 2^{10}5^{-1}$

6 0

3 years ago

Some conference-goers saunter over to the Healthy Snack Box Machine, where they each choose one of ﬁve kinds of fruit, one of th

nalin [4]

Answer: There are 90 snack boxes.

Step-by-step explanation:

Given : The number of kinds of fruits = 5

The number of kinds of herbal teas = 3

The number of kinds of flavors of wrap sandwich = 6

Then by using the fundamental principal of counting, the number of possible snack are there will be :_

$5\times3\times6= 90$

Therefore, the number of possible snacks = 90

4 0

3 years ago

Simplify ( 8∙4∙2 8∙7 )^2 × ( 8 0 7−3 )^3 × 7 −9 .

stich3 [128]

$\bf ~\hspace{7em}\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
~\hspace{4.5em}
a^n\implies \cfrac{1}{a^{-n}}
~\hspace{4.5em}
\cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{8\cdot 4\cdot 2}{8\cdot 7} \right)^2\times \left( \cfrac{8^0}{7^{-3}} \right)^3\times 7^{-9}\implies \left( \cfrac{8\cdot 8}{8\cdot 7} \right)^2\times \left( \cfrac{1\cdot 7^3}{1} \right)^3\times \cfrac{1}{7^9}$

$\bf \left( \cfrac{8}{8}\cdot \cfrac{8}{7} \right)^2\times (7^3)^3\times \cfrac{1}{7^9}\implies \left( \cfrac{8}{7} \right)^2\times 7^{3\cdot 3}\times \cfrac{1}{7^9}\implies \cfrac{8^2}{7^2}\times \cfrac{7^9}{7^9}
\\\\\\
\cfrac{8^2}{7^2}\implies \cfrac{64}{49}$

4 0

4 years ago

Help quickly 3////////////////////////////////////////////////

evablogger [386]

Answer:

I think d

Step-by-step explanation:

6 0

3 years ago

Find the value of x.

andrew11 [14]

Answer:

Step-by-step explanation:

The upper left hand arc is also 130

The lower right hand arc is also x

A circle all the way around from some starting point is 360 degrees.

x + x + 130 + 130 = 360 Equation. Combine like terms.

2x + 260 = 360 Subtract 260 from both sides

2x = 360 - 260

2x = 100 Divide by 2

x = 100/2

x = 50

5 0

3 years ago