Answer:
a. the environmental variance (VE) = 3.5 g ²
b. 17.5 g ² for population
c. the heritability of broad sense (H2) = 0.83
Explanation:
a.With the information we have we can infer that environmental factors influence A, which is considered isogenic, thus, the environmental variance (VE) = 3.5 g ²
b.When studying population B, comparing it without environmental changes with respect to population A, we found that its total variance (VT) = 21.0g ²
We generate the following formula with the data obtained previously to find the genetic variation
VT = VE + VG
then VG = VT-VE
replacing data:
VG = 21.0 - 3.5 = 17.5 g ² for population
c. Regarding the heritability of broad sense (H2) in population B, we can reach the result with the data previously obtained like this:
H2 = VG / VT = 17.5 / 21.0 = 0.83
Answer: The female had the genotype XHXh, and produced the two gametes seen at the left side of the diagram. The male had the genotype XHY0, and produced the two gametes seen at the right side of the diagram.
Explanation:
That would be the nucleus.
The nucleus is the control center of the cell, located in the center of a cell.
Answer:
a. disruption of mitotic spindle formation.
Explanation:
Vinblastine is a chemotherapeutic drug which is used to restrict cancer cell proliferation. During metaphase, it binds to microtubular proteins which play a very important role in mitotic spindle formation. If spindles will not form then during anaphase, the sister chromatids will not separate and mitosis will not take place. This is how hyper-proliferative cancerous cells are controlled from dividing and cancer is treated using this drug.
