Rotation and translation are rigid transformations, they don't change figure sizes. Dilation change figure sizes increasing or decreasing them by scale factor.
First, find AB and A'B' by the formula:

As you can see AB=2A'B'. This means that the segment AB was decreased twice to form segment A'B'. Then the scale factor is 1/2.
Answer:
see explanation
Step-by-step explanation:
Using the Pythagorean identity
sin²θ + cos²θ = 1 ( divide terms by sin²θ )
+
=
, that is
1 + cot²θ = cosec²θ ← as required
$13 is your answer. Multiply 3x5 then subtract the total from 28
No I don’t think so cause I just calculated the answer