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Elena-2011 [213]
3 years ago
15

Which of the following combined with the equation −9x + 3y = 12 creates a system of linear equations with no solution?

Mathematics
1 answer:
Mumz [18]3 years ago
8 0

Answer:

Step-by-step explanation:

You can't get an exact answer to this because there are no choices.

Add 9x to both sides.

3y = 9x + 12              Divide by 3

3y/3 = 9x/3 + 12/3    Combine

y = 3x + 4

Now to get anything at all that is parallel to this and providing no answer because there is no intersection of the two lines, just change the 4 to something else. Here's one example

y = 3x + 8

As long as the number in front of the x's is the same, they are parallel with no point in common.

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A patient was supposed to take 560 mg of medicine but only tool 420 mg.What percent of the medicine did the patient take?
Stolb23 [73]
75% I think.

because if you do 560 - 420 you get 140.

140 / 560 x 100 = 25

which means there is a 25% decrease, so they took 75%.
7 0
3 years ago
Read 2 more answers
I really need help with this, and also if it's Substitution or linear combination and it will be really helpful if you do step b
Delicious77 [7]

Answer:

-2x+y=12

Step-by-step explanation:

linear equation

5 0
2 years ago
indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and
vladimir1956 [14]

The equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and (5, 5) is <u>12x - 2y = 13</u>.

In the question, we are asked to indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and (5, 5).

The slope of the line with endpoints (-1,6) and (5,5), can be calculated as:

m = (6 - 5)/(-1 - 5) = 1/(-6) = -1/6.

Thus, the slope of the perpendicular bisector = -1/m = -1/(-1/6) = 6.

The perpendicular bisector passes through the midpoint of the line with endpoints (-1,6) and (5,5), which can be calculated as:

(x₁, y₁) = ( {(-1 + 5)/2},{(6 + 5)/2} ),

or, (x₁,y₁) = (2, 11/2).

Thus, the required equation can be shown as:

(y - 11/2) = 6(x - 2), which can be shown in the standard form as follows:

(2y - 11)/2 = 6x - 12,

or, 2y - 11 = 12x - 24,

or, 12x - 2y = 13.

Thus, the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (-1,6) and (5, 5) is <u>12x - 2y = 13</u>.

Learn more about the equation of perpendicular bisector at

brainly.com/question/20608689

#SPJ4

4 0
1 year ago
Help me pleaseeeeeeeeeeeeeeee
inn [45]

Answer:

1) n^2 – 3 n + 8   4^2 – 3*4 + 8 = 12    

2)    (x^2 – 4 y) / 2      (16 + 12) / 2 = 14

3) 4 * |-7 – 2| = 4 * 9 = 36     Abs -9 = 9  

4) 19 – x^2 = 19 – 25 = -6     (-5)^2 = 25

5) S^2 t – 10 = -8^2 * ¾ -10 = 64 * ¾ - 10 = 38

6) 4 p^2 + 7 q^3 = 4 * 9 + 7 * (-8) =  - 20      (-2)^3 = -8

4 0
3 years ago
Please help me with this problem
tiny-mole [99]
14/100 + 3/10 + 2/10
Same denominators to add=
14/100 + 30/100 + 20/100
64/100
Simplify to=
16/25 is the correct answer
4 0
3 years ago
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