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ozzi
3 years ago
14

What happens to your survivor his her family

Mathematics
1 answer:
RoseWind [281]3 years ago
3 0
Provide more info. And I would love to help
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Which expression is a difference of a number and a product
adoni [48]

Answer:

10-8x

Step-by-step explanation:

because it is 10 minus 8x

but 8x is 8 times x

plz brainliest :)

7 0
3 years ago
Read 2 more answers
If f(x)=-x+12 find f(2) & give the ordered pair
mestny [16]


Plug in 2 for x

-2+12=f(2)

10=F(2)

F(2)=y

(x,y)

(2,10)

5 0
3 years ago
Mr. Gentry teaches two science classes. There are 28 students in his biology class and 21 students in his environmental science
saveliy_v [14]

Answer:

1gsig1ogsjq sv1sg1isvk1z i1gz

Step-by-step explanation:

Gjqziqgzi1gzva j1vziqvzn1gaigakhixg1z

8 0
3 years ago
Express this to single logarithm
zzz [600]

Answer:  \log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

  1. log(A) + log(B) = log(A*B)
  2. log(A) - log(B) = log(A/B)
  3. B*log(A) = log(A^B)

From there, we can then say the following:

\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}

8 0
2 years ago
1. Dan charges $15 per hour for walking dogs. What is the missing number in the table?
Dmitry_Shevchenko [17]
It’s c lololololololololop
8 0
2 years ago
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