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Katarina [22]
2 years ago
5

Which expression is equivalent to: (5⁹ × 5⁻⁷)⁻² ?

Mathematics
1 answer:
lutik1710 [3]2 years ago
4 0

Answer:

(6^4 x 2^-9)

Step-by-step explanation:

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Express the area of the entire rectangle. you answer should be a polynomial in standard form.
mixer [17]

Answer:x^2 + 9x + 20

Step-by-step explanation:

You could just multiply (x+4)(x+5) and get x^2 + 9x + 20, but judging from the picture, it looks like they want you to split it into 4 rectangles

x^2 +4x+ 5x + 20 =x^2 +9x + 20, just like (x+4)(x+5)

8 0
3 years ago
One third of a number reduced by 11 is equal to 4 more than the number
Alecsey [184]
1/3x -11 = 4+x is what we start with, then add 11 to both sides, then subtract x from both sides. Then when we divide both sides by -2/3, x will equal -22.5.
6 0
3 years ago
Rewrite the decimal fraction as a decimal number.
Sergio039 [100]

Answer:

8.025

Step-by-step explanation:

If you count the zeros in 1000, it's three. Count three starting from the back of 25. Add 0 in front of 25 to make it a three digit number. You then put the decimal point with the whole number.

7 0
3 years ago
In spherical geometry, what is the term used for the shortest distance between two points?
sweet [91]
The correct answer for the question shown above is: Geodesic.

 The explanation of is shown below:
 1. You have that ,by definition, the spherical geometry studies figures on the surface of the spheres.
 2. And the termn known as "Geodesic" is define as <span>the shortest distance between two points on the surface of a sphere or a curved surface. </span>
3 0
3 years ago
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal
ohaa [14]

Answer: AAA similarity.


Step-by-step explanation:  CB is the transversal for the parallel lines AB and DE, and so by transverse property, we have ∠CED ≅ ∠CBA. Similarly, CA acts as a tranversal for the same pair of parallel lines AB and DE and using the same property, we can have ∠CDE ≅ ∠CAB. Now, in triangles CED and ABC, we have

∠CED ≅ ∠CBA,

∠CDE ≅ ∠CAB

and

∠DCE ≅ ∠ACB [same angle]

Hence, by AAA (angle-angle-angle) similarity,

△CED ~ △ABC.

Thus, the correct option is AAA similarity.


8 0
3 years ago
Read 2 more answers
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