Which expression is equivalent to: (5⁹ × 5⁻⁷)⁻² ?

Allison scores 14 points higher on her math test than her science test. Her

posledela

Answer:

allisons score would be 114 because it was 14 points higher you would add to her math

Step-by-step explanation:

114

8 0

2 years ago

La ecuación de la recta que lasa a través de los puntos P1 (2,5) y P2 (4,11) es: a) 3x+y+1=0 b)3x-y-1=0 c) 3x-y+1=0

Zolol [24]

Respuesta:

3x-y-1 = 0

Explicación paso a paso:

La forma estándar de ecuación de una línea se expresa como y = mx + b

M es la pendiente

b es la intersección con el eje y

Dada la coordenada P1 (2,5) y P2 (4,11)

Pendiente m = y2-y1 / x2-x1

m = 11-5 / 4-2

m = 6/2

m = 3

Sustituya m = 3 y (2,5) en y = mx + b

5 = 3 (2) + b

5 = 6 + b

b = 5-6

b = -1

Obtén la ecuación

y = 3x-1

Igualar a cero

y - 3x +1 = 0

Multiplicar por -1

3x-y-1 = 0

Esto da la ecuación requerida

5 0

2 years ago

Find the product. Write the product in simplest form.<br> 8 X<br> 5/7

goblinko [34]

Answer:

Simplify above fraction

56

6

Common divisor of (56, 6) is 2

Divide both numerator & denominator by gcd value 2

56

6

=

56

÷

2

6

÷

2

=

28

3

8

3

×

7

2

=

28

3

Step-by-step explanation:

6 0

2 years ago

10.3.23

Helga [31]

Answer:

The probability that a high school member selected at random is on the swim team is $\frac{9}{40} = 0.225$

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: High school student.

Event B: Is on the swin team.

Probability of selecting a high school student:

Of the 1500 students, 200 are on high school. So

$P(A) = \frac{200}{1500}$

Probability of selecting a high school student who swims:

Of the 1500 students, 45 are high school students who swim. So

$P(A \cap B) = \frac{45}{1500}$

What is the probability that a high school member selected at random is on the swim team?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{45}{1500}}{\frac{200}{1500}} = \frac{45}{200} = \frac{9}{40} = 0.225$

The probability that a high school member selected at random is on the swim team is $\frac{9}{40} = 0.225$

4 0

2 years ago

Pens and Pencils

Lina20 [59]

Pen=x
Pencil=y
y+0.15=x
y+x=0.69
y+y+0.15=0.69
2y=0.69-0.15
2y=0.54
y=0.54/2
y=0.27 pencils
y+0.15=x
0.27+0.15=x
0x=0.42 pen
150 pencils x0.27=40.5$
225 pens x 0.42=94.5$
Total 40.5$ + 94.50$=135 $
Supplier is right about a priče.

6 0

2 years ago