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Katarina [22]
2 years ago
5

Which expression is equivalent to: (5⁹ × 5⁻⁷)⁻² ?

Mathematics
1 answer:
lutik1710 [3]2 years ago
4 0

Answer:

(6^4 x 2^-9)

Step-by-step explanation:

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What is 0.433 rounded to the nearest tenths
Fynjy0 [20]
0.433 is already rounded to the hundredths so to round it to the nearest tenths, remove the last number.

Your answer is 0.43
6 0
3 years ago
Read 2 more answers
Garrett chooses to invest $1800 in a simple. The account earns 3% interest over 5 years which equation represents garrets invest
Alla [95]

The interest earned in 5 years would be $270

<u>Explanation:</u>

Given:

Principal, P = $1800

Rate of interest, r = 3%

Time, t = 5 years

Simple interest, I = ?

We know,

I = \frac{p X r X t}{100}

On substituting the value we get

I = \frac{1800 X 3 X 5}{100} \\\\I = 270

Therefore, interest earned in 5 years would be $270

6 0
3 years ago
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to two decimal places
Montano1993 [528]

The solution of the given equation is :

cosθ = 1/2 when θ = π/3 + 2kπ or 5π/3 + 2kπ

cosθ = -1 when θ = π + 2kπ

Since cos2θ + sin2θ = 1, sin2θ = 1 - cos2θ

So, the given equation is equivalent to 2(1 - cos2θ) - cosθ = 1

-2cos2θ - cosθ + 1 = 0

2cos2θ + cosθ - 1 = 0 (multiplying the entire equation by -1)

(2cosθ - 1)(cosθ + 1) = 0 (taking common)

cosθ = 1/2 or cosθ = -1 (on equating it to zero)

cosθ = 1/2 when θ = π/3 + 2kπ or 5π/3 + 2kπ

cosθ = -1 when θ = π + 2kπ

For more information about trigonometric ratios, visit

brainly.com/question/24496175

3 0
1 year ago
A researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playi
Andreas93 [3]

Answer:

Proportion of the students recalled more than 15 names is 91.77%.

Step-by-step explanation:

We are given that a researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playing the name game, the students were asked to recall as many first names of fellow students as possible.

The mean number of names recalled was 19.41 with a standard deviation of 3.17.

<em>Let X = number of names recalled</em>

SO, X ~ N(\mu = 19.41,\sigma^{2} = 3.17^{2})

The z-score probability distribution is given by ;

                  Z = \frac{X-\mu}{\sigma} } } ~ N(0,1)

where, \mu = mean number of names recalled = 19.41

            \sigma = standard deviation = 3.17

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, proportion of the students recalled more than 15 names is given by = P(X > 15 names)

     P(X > 15) = P( \frac{X-\mu}{{\sigma} } } > \frac{15-19.41}{3.17}  } ) = P(Z > -1.39)

                                                      = P(Z < 1.39) = 0.9177  {using z table}

<em>Therefore, proportion of the students recalled more than 15 names is </em><em>91.77%.</em>

4 0
3 years ago
How do i factor (10x^2-25x-15)
Otrada [13]
5(2x^2 - 5x - 3) = 5(2x + 1)(x - 3)

hope this helps :)
4 0
3 years ago
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