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2 years ago

PLS HELP ME GUYS ITS MY LAST QUESTION IN GEOMETRY

Mathematics

1 answer:

aliina [53]2 years ago

7 0

Answer:

Example = ( 12, 1 )

Step-by-step explanation:

There are many possible solutions to this equation, and all you would have to do to determine the ordered pair, is satisfy the following criteria -

$x - 6y = 6,\\- 6y = - x + 6,\\y = 1 / 6x - 1$

Take a look at a graph of the line y = 1 / 6x - 1. Any ordered pair that lies on this line is a solution to the equation. The " criteria " is that the ordered pair must lie on this line. Let me give you an example, ( 12, 1 ).

Hope that helps!

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Find the missing part.

sveta [45]

Answer:

The answer is $a = \frac{15}{4}$

Step-by-step explanation:

We have to:

$cos(\theta) = \frac{adjacent\ side}{hypotenuse}$

So, if we take the 60 degree angle of the smallest triangle, we have to:

$cos(60) = \frac{a}{x}$

We do not know x. But if we take the sine of the angle of 30 degrees and the main triangle we have:

$sin(30) = \frac{x}{15}\\\\x =\frac{15}{2}$

Then:

$cos(60) = \frac{a}{\frac{15}{2}}$

$a = cos(60)\frac{15}{2}$

$a = \frac{15}{4}$

7 0

2 years ago

The formula for the area of a parallelogram is A = bh, where b is the base and h is the height. A parallelogram that is not draw

Bezzdna [24]

Answer:

Option 2) 2x3 – 6x2 – 14x + 24 square centimeters

Step-by-step explanation:

We know the Parallelogram Area is given by

$A=bh$ Eqn. (1)

where

$b$ : is the base

$h$ : is the height

We are also given that the base is

$b=2x^2+2x-6$

and the height is

$h=x-4$

So we can plug these two expressions in Eqn. (1), simplify and find our Area equation as follow:

$A=(2x^2+2x-6)(x-4)\\\\A=(2x^2)(x)+(2x)(x)-(6)(x)+(2x^2)(-4)+(2x)(-4)-(6)(-4)\\\\A=2x^3+2x^2-6x-8x^2-8x+24\\\\A=2x^3+2x^2-8x^2-6x-8x+24\\\\A=2x^3-6x^2-14x+24$