There are C(5,2) = 10 ways to choose 2 contraband shipments from the 5. There are C(11, 1) = 11 ways to choose a non-contraband shipment from the 11 that are not contraband. Hence there are 10*11 = 110 ways to choose 3 shipments that have 2 contraband shipments among them.
There are C(16,3) = 560 ways to choose 3 shipments from 16. The probability that 2 of those 3 will contain contraband is
110/560 = 11/56 ≈ 19.6%
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C(n,k) = n!/(k!(n-k)!)
Use this equation to solve the problem:
x - (x * .25) = 40
This equation is saying the original price times itself by 25% is 40.
x - (x * .25) = 40
Simplify.
x - .25x = 40
.75x = 40
Divide both sides by .75.
x = 53.33
The original price was $53.33
Answer:
OH HECK no im not that smart for this type of math , noo honeyboo
Step-by-step explanation:
Assuming you are referring to simple interest not compound that that it is annual you would gain $100 putting you at $600
Answer: Ksh 6144
Step-by-step explanation:
On Thursday, a fruit vendor bought 1948 oranges on a Thursday and sold 750. The number of oranges left will be: = 1948 - 750 = 1198
On n Friday, he sold 240 more oranges than on Thursday. This means the number of oranges sold is: = 240 + 750 = 990.
The number for f oranges left will then be: = 1198 - 990 = 208
On Saturday, he bought 560 more
oranges, the total oranges that the vendor has now will be:
= 208 + 560 = 768
Since sold all the oranges he had at a price of Ksh. 8 each, the amount if money made will be:
= Ksh 8 × 768
= Ksh 6144
The vendor made Ksh 6144
