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xz_007 [3.2K]
3 years ago
5

The diameter of a circle is 12 in. Find the circumference to the nearest tenth please helppp

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
4 0

Answer:

37.68in

Step-by-step explanation:

circumference = 2πr

r= radius = diameter/2 = 12/2 =6 in

C= 2πr = 2 x 3.14 x 6= 37.68in

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Answer:

its the third one i got that

6 0
3 years ago
Read 2 more answers
Newton’s law of cooling states that the temperature of an object changes at a rate proportionalto the difference between the tem
Verizon [17]

Answer:

\frac{dT}{dt} = -0.05\;min^{-1}  (T-70\ºF)

Step-by-step explanation:

Hi!

Lets call:

T = temprature of the object

T₀ = temperature of surroundings

t = time

The rate of change of T is its derivative with respecto to time. If T > T₀, the object looses heat, so T decreases. Then, being k > 0:

\frac{dT}{dt} = -k(T-T_0) \\

In this case T₀ = 70ºF and k = 0.05/min. Then the differential equation is:

\frac{dT}{dt} = -0.05\;min^{-1}  (T-70\ºF)

3 0
3 years ago
Pls help this question i want its aregent
meriva

Step-by-step explanation:

Answer 3

multiply 4 by -20

1/4×-20

= -20/-20

= 1 answer

4 0
3 years ago
Suppose that $1800 is borrowed for three years at an interest rate of 2% per year, compounded continuously. Find the amount owed
Schach [20]

1908

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5 0
2 years ago
Suppose that we want to test the hypothesis with a significance level (alpha) of .05 that the climate has changed since industri
saw5 [17]

Answer: we reject the initial claim

(50. 3802, 51.6198)

Step-by-step explanation:

A)

The initial statement is that the mean temperature throughout history is 50°

This is the null hypothesis and it is denoted as H'

H': u = 50.

After taking a sample of 40 years, we realized that the mean temperature is 51°.

This is the alternative hypothesis, in contradiction to the alternative.

The alternative hypothesis is denoted as H1

H1: u > 50 ( upper tailed).

Sample size (n) = 40

Sample mean (x) = 51

Population standard deviation (σ) = 2

We use a z test to get the value of the test statistics.

We are using a z test because sample size is greater than 30 ( n = 40) and population standard deviation is given.

Z score = x - u/ (σ/√n)

Z score = 51 - 50 / (2/√40)

Z score = 1 / 0.3162

Z score = 3.16

Our level of significance is 5%, and the critical value at this level of significance is 1.645.

By comparing the z score relative to the critical value, since our z score is greater than 1.645, it implies that we are in the rejection region hence we reject the initial claim.

B)

We are to construct a 95% confidence interval for population mean temperature.

For upper limit

u = x + Zα/2 ×(σ/√n)

Where Zα/2 = 1.96 which is the critical value for a two tailed test at 5% level of significance.

For upper limit, we have that

u = 51 + 1.96 × (2/√40)

u = 51 + 1.96 (0.3162)

u = 51 + 0.6198

u = 51.6198.

For lower limit, we have that

u = 51 - 1.96 × (2/√40)

u = 51 - 1.96 (0.3162)

u = 51 - 0.6198

u = 50. 3802.

Hence the 95% confidence level for mean temperature is given as (50. 3802°, 51.6198°)

7 0
3 years ago
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