<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
Answer:
x=2°
Step-by-step explanation:
The given angles are corresponding angles.
Corresponding angles are congruent.
7x+3=8x+1
2=x
x=2
Did you mean 36/12? If so the answer would be 3/1 or 3.
.6 is more than .48.
If you appreciated my answer, please thank and brainliest me!
Answer:
![2xyzx^{2} \sqrt[ 0]{xyz}](https://tex.z-dn.net/?f=2xyzx%5E%7B2%7D%20%5Csqrt%5B%200%5D%7Bxyz%7D)
Step-by-step explanation:
simplify the radical by breaking the radicand up into a product of know factors
